火柴题解

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// huocai.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"
#include
#include
#define NUM 20
using namespace std;

void main()
{
//规则的输出
cout< cout<<"***************************************************"< cout<<"游戏规则：共有67根火柴，2个人依次拿取，每个人每次只"< cout<<"能拿1跟或者2跟或者3跟火柴。拿到最后一跟火柴的人算输"< cout<<"****************************************************"< cout< //变量的定义
int match_num=67; //火柴数目
int *p_match_num; //指向火柴数目的指针
int player = 0; //玩家变量，偶数代表玩家1，奇数代表玩家2
char player_first[NUM]; //玩家1的名字
char player_second[NUM]; //玩家2的名字
char judge; //判断变量，值为'y'时，表示玩家1先开局
int put_num=0; //拿走火柴的数目
char temp[NUM];
char *p_player_now;
int *p_put_num; //指向拿走火柴数目的指针
int *p_player;
//指针赋值
p_match_num=&match_num;
p_put_num=&put_num;
p_player=&player;
p_player_now=player_first;
//函数的定义

void match(int* p_player, int* p_match_num,int* p_put_num,char* p_player_now); //火柴拿走数目函数
//游戏开始
cout<<"请输入玩家1的名字：";
gets(player_first);
cout<<"请输入玩家2的名字：";
gets(player_second);
//玩家开局顺序的选择
cout<<"玩家“"< cin>>judge;
if(judge=='s')1
{
strcpy(temp,player_first);
strcpy(player_first,player_second);
strcpy(player_second,temp);
}
cout<<"玩家“"< cout< //火柴的拿取
while(1)
{
if(player%2==0)
p_player_now=player_first;
else
p_player_now=player_second;
match(p_player,p_match_num,p_put_num,p_player_now);
match_num=match_num-put_num;
if(match_num==0)
{
cout<<"玩家“"< break;
}
}
}

void match(int* p_player,int* p_match_num,int* p_put_num,char* p_player_now)
{
cout<<"请“"< cin>>*p_put_num;
while(*p_put_num!=1 && *p_put_num!=2 && *p_put_num!=3 || *p_match_num-*p_put_num<0)
{
if(*p_put_num!=1 && *p_put_num!=2 && *p_put_num!=3)
{
cout<<"您输入的数值不合法，拿走的火柴数目只能是 1 或 2 或 3，请重新输入:";
cin>>*p_put_num;
}
if(*p_match_num-*p_put_num<0)
{
cout<<"您输入的数值大于剩余火柴数目，请重新输入：";
cin>>*p_put_num;
}
}
cout<<"您拿走的火柴数目是： "<<*p_put_num< cout<<"剩余火柴数目是： "<<*p_match_num-*p_put_num< cout< (*p_player)++;
}