Leetcode 166. Fraction to Recurring Decimal

Given two integers representing the numerator and denominator of a fraction, return the fraction in string format.

If the fractional part is repeating, enclose the repeating part in parentheses.

For example,
Given numerator = 1, denominator = 2, return "0.5".
Given numerator = 2, denominator = 1, return "2".
Given numerator = 2, denominator = 3, return "0.(6)".

思路：把分数转化为小数表示，循环部分用括号括起来。
自己开始的想法是用hashmap记录每次除数的位置，但是除数有可能存在连续几个0的情况，所以是有问题的，正确的方法是map记录每次余数的位置。
题目的几个坑：除数为0、被除数为0、正好整除无小数、商是负数以及商溢出的这几种情况都要考虑到。
先放自己有问题的代码：

public String fractionToDecimal(int numerator, int denominator) {
    if (denominator == 0) {
        return String.valueOf(Integer.MAX_VALUE);
    }
    if (numerator == 0) {
        return "0";
    }
    boolean negative = false;
    if ((numerator > 0 && denominator < 0) || (numerator < 0 && denominator > 0)) {
        negative = true;
    }
    numerator = Math.abs(numerator);
    denominator = Math.abs(denominator);

    int dotLeft = numerator / denominator;
    int yushu = numerator % denominator;
    if (yushu == 0) {
        return String.valueOf(dotLeft);
    }

    String dotRight = "";
    int[] map = new int[10];
    int cnt = 1;
    while (yushu > 0) {
        int cur = yushu * 10;
        int devide = cur / denominator;
        if (map[devide] > 0) {
            dotRight = dotRight.substring(0, map[devide]-1) + "(" + dotRight.substring(map[devide]-1) + ")";
            break;
        }
        dotRight += String.valueOf(devide);
        map[devide] = cnt;
        yushu = cur % denominator;
        cnt++;
    }

    return (negative ? "-" : "") + String.valueOf(dotLeft) + "." + String.valueOf(dotRight);
}

下面是solution给出的标准解答，对比起来自己的代码丑哭了。。。

public String fractionToDecimal(int numerator, int denominator) {
if (numerator == 0) {
    return "0";
}
StringBuilder fraction = new StringBuilder();
// If either one is negative (not both)
if (numerator < 0 ^ denominator < 0) {
    fraction.append("-");
}
// Convert to Long or else abs(-2147483648) overflows
long dividend = Math.abs(Long.valueOf(numerator));
long divisor = Math.abs(Long.valueOf(denominator));
fraction.append(String.valueOf(dividend / divisor));
long remainder = dividend % divisor;
if (remainder == 0) {
    return fraction.toString();
}
fraction.append(".");
Map map = new HashMap<>();
while (remainder != 0) {
    if (map.containsKey(remainder)) {
        fraction.insert(map.get(remainder), "(");
        fraction.append(")");
        break;
    }
    map.put(remainder, fraction.length());
    remainder *= 10;
    fraction.append(String.valueOf(remainder / divisor));
    remainder %= divisor;
}
return fraction.toString();
}