ACM HDU 2516 取石子游戏（博弈）

取石子游戏

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 812    Accepted Submission(s): 435

Problem Description

1堆石子有n个,两人轮流取.先取者第1次可以取任意多个，但不能全部取完.以后每次取的石子数不能超过上次取子数的2倍。取完者胜.先取者负输出"Second win".先取者胜输出"First win".

 

Input

输入有多组.每组第1行是2<=n<2^31. n=0退出.

 

Output

先取者负输出"Second win". 先取者胜输出"First win".
参看Sample Output.

 

Sample Input

2 13 10000 0

 

Sample Output

Second win Second win First win

 

Source

ECJTU 2008 Autumn Contest

 

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#include<stdio.h>
int main()
{
    int m[45],i,n;
    m[0]=2;
    m[1]=3;
    for(i=2;i<45;i++)
        m[i]=m[i-1]+m[i-2];
    while(scanf("%d",&n),n)
    {
        for(i=0;i<45;i++)
        {
            if(m[i]==n)break;
        }    
        if(i==45)  printf("First win\n");
        else       printf("Second win\n");
    }    
    return 0;
}