状压dp

poj 2686 Traveling by Stagecoach

#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#define fi first
#define se second
#define pb push_back
#define me(a,b) memset(a,b,sizeof(a))
#define INIT() std::ios::sync_with_stdio(false)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int>P;
const int MAX_N=8+5;
const int MAX_M=30+5;
const int INF=0x7fffffff;
const int inf=1000000000;
const double EPS=1e-6;
const ull base=123;
const ll mod=998244353;
const double pi=4*atan(1.0);
int n,m,p,a,b;
int t[MAX_N];
int edge[MAX_M][MAX_M];
double dp[1<<MAX_N][MAX_M];
int main()
{
    while(~scanf("%d%d%d%d%d",&n,&m,&p,&a,&b))
    {
        if(n==0&&m==0&&p==0&&a==0&&b==0)
            break;
        int i;
        me(edge,-1);
        for(i=0; i<=(1<<n); i++)
        {
            fill(dp[i],dp[i]+1+m,1.0*inf);
        }
        for(i=1; i<=n; i++)
        {
            scanf("%d",&t[i]);
        }
        for(i=1; i<=p; i++)
        {
            int l,r,value;
            scanf("%d%d%d",&l,&r,&value);
            edge[l][r]=value;
            edge[r][l]=value;
        }
        dp[(1<<n)-1][a]=0;
        double mn=1.0*INF;
        for(i=(1<<n)-1; i>=0; i--)
        {
            for(int s=1; s<=n; s++)
                if((i>>(s-1))&1)
                {
                    for(int u=1; u<=m; u++)
                    {
                        for(int v=1; v<=m; v++)
                        {
                            if(edge[u][v]>=0)
                            {
                                //cout<
                                dp[i^(1<<(s-1))][v]=min(dp[i^(1<<(s-1))][v],dp[i][u]+1.0*edge[u][v]/t[s]);
                                //cout<
                                //cout<<(i^(1<<(s-1)))<<' '<
                            }
                        }
                    }
                }
            mn=min(mn,dp[i][b]);
        }
        //cout<
        if(mn==inf)
            cout<<"Impossible"<<endl;
        else
            printf("%.3f\n",mn);
    }
}

Doing Homework

#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#define fi first
#define se second
#define pb push_back
#define me(a,b) memset(a,b,sizeof(a))
#define INIT() std::ios::sync_with_stdio(false)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int>P;
const int MAX_N=15+5;
const int MAX_M=30+5;
const int INF=0x7fffffff;
const int inf=1000000000;
const double EPS=1e-6;
const ull base=123;
const ll mod=998244353;
const double pi=4*atan(1.0);
int n;
string s[MAX_N];
int dead[MAX_N];
int day[MAX_N];
int dp[1<<16];
int now[1<<16];
int pre[1<<16];
int ans[MAX_N];
int main()
{
    INIT();
    int t;
    cin>>t;
    while(t--)
    {
        cin>>n;
        int i;
        for(i=1; i<=n; i++)
        {
            cin>>s[i]>>dead[i]>>day[i];
        }
        fill(dp,dp+1+(1<<n),inf);
        me(now,0);
        dp[0]=0;
        int mn=INF;
        for(i=0; i<=(1<<n)-1; i++)
        {
            for(int j=1; j<=n; j++)
            {
                if(((i>>(j-1))&1)==0)
                {
                    int p=0;
                    if(now[i]+day[j]>dead[j])
                    {
                        p=now[i]+day[j]-dead[j];
                    }
                    if(dp[i]+p<dp[i^(1<<(j-1))])
                    {
                        dp[i^(1<<(j-1))]=dp[i]+p;
                        now[i^(1<<(j-1))]=now[i]+day[j];
                        pre[i^(1<<(j-1))]=j;
                        //cout<<1<
                    }
                }
            }

        }
        cout<<dp[(1<<n)-1]<<endl;
        int flag=(1<<n)-1;
        int pos=0;
        while(flag)
        {
            int x=pre[flag];
            ans[pos++]=x;
            flag=flag^(1<<(pre[flag]-1));
        }
        for(i=pos-1;i>=0;i--){
            cout<<s[ans[i]]<<endl;}
    }
    return 0;
}

poj 2411 Mondriaan’s Dream

这题优先级的问题可坑死我了，==的优先级高于&，一定要记得加括号！！！

#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#define fi first
#define se second
#define pb push_back
#define me(a,b) memset(a,b,sizeof(a))
#define INIT() std::ios::sync_with_stdio(false)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int>P;
const int MAX_N=15+5;
const int MAX_M=30+5;
const int INF=0x7fffffff;
const int inf=1000000000;
const double EPS=1e-6;
const ull base=123;
const ll mod=998244353;
const double pi=4*atan(1.0);
ll dp[13][13][1<<13];
int main()
{
    int n,m;
    while(~scanf("%d%d",&n,&m)&&n)
    {
        me(dp,0);
        dp[0][m][(1<<m)-1]=1;
        int i,j,k;
        for(i=1; i<=n; i++)
        {
            for(j=1; j<=m; j++)
            {
                int pi,pj;
                if(j==1)
                {
                    pi=i-1;
                    pj=m;
                }
                else
                {
                    pi=i;
                    pj=j-1;
                }
                for(k=0; k<(1<<m); k++)
                {
                    if(1&(k>>(m-1))==1)
                    {
                        dp[i][j][(k<<1)^(1<<m)]+=dp[pi][pj][k];
                        //cout<<((k<<1)^(1<
                        //cout<
                    }
                    if(i>1&&(1&(k>>(m-1))==0))
                    {
                        dp[i][j][(k<<1)+1]+=dp[pi][pj][k];
                        //cout<<((k<<1)+1)<
                    }
                    if(j>1&&((1&(k>>(m-1)))==1)&&((k&1)==0))
                    {
                        //cout<<1<
                        dp[i][j][((k+1)<<1)^(1<<m)+1]+=dp[pi][pj][k];
                        //cout<<(((k+1)<<1)^(1<
                    }
                }
            }
        }
        cout<<dp[n][m][(1<<m)-1]<<endl;
    }
}