使用listagg()within group() 函数帮助网友解决一个问题

今天一网友在朋友发布一道悬赏题，


要实现如下内容：

对方悬赏10块钱，求一条SQL，咱先不说钱多少的事。这样的问题在SQL开发当中经常遇到，在oracle 10g  和11g 实现方法不一样。
11g 采用 listagg() within group ()来实现：



with tmp0 as
 (select '1' as IDS, '2' as IDS2 from dual
  union all
  select '1' as IDS, '3' as IDS2 from dual
  union all
  select '1' as IDS, '4' as IDS2 from dual
  union all
  select '2' as IDS, '2' as IDS2
    from dual
  union all
  select '2' as IDS, '5' as IDS2
    from dual
  union all
  select '2' as IDS, '8' as IDS2
    from dual
  union all
  select '3' as IDS, '2' as IDS2
    from dual
  union all
  select '3' as IDS, '3' as IDS2
    from dual
  union all
  select '3' as IDS, '4' as IDS2
    from dual
  union all
  select '4' as IDS, '9' as IDS2
    from dual
  union all
  select '8' as IDS, '9' as IDS2
    from dual),
b as
 (select IDS, listagg(IDS2, ',') within group(order by IDS) as ids2
    from tmp0
   group by IDS)

select b.*
  from b, b a
 where b.ids2 = a.ids2
   and b.ids <> a.ids
 order by b.ids

结果图接不贴了，ITPUB的插入图片做的确实不咋滴!这和那啥啥第一网站不太相符啊，呵呵！

来自 “ ITPUB博客 ” ，链接：http://blog.itpub.net/29507357/viewspace-2124768/，如需转载，请注明出处，否则将追究法律责任。

转载于:http://blog.itpub.net/29507357/viewspace-2124768/