Restoring Road Network(AtCoder-3535)

Problem Description

In Takahashi Kingdom, which once existed, there are N cities, and some pairs of cities are connected bidirectionally by roads. The following are known about the road network:

People traveled between cities only through roads. It was possible to reach any city from any other city, via intermediate cities if necessary.
Different roads may have had different lengths, but all the lengths were positive integers.
Snuke the archeologist found a table with N rows and N columns, A, in the ruin of Takahashi Kingdom. He thought that it represented the shortest distances between the cities along the roads in the kingdom.

Determine whether there exists a road network such that for each u and v, the integer Au,v at the u-th row and v-th column of A is equal to the length of the shortest path from City u to City v. If such a network exist, find the shortest possible total length of the roads.

Constraints

  • 1≤N≤300
  • If ij, 1≤Ai,j=Aj,i≤109.
  • Ai,i=0

Input

Input is given from Standard Input in the following format:

N
A1,1 A1,2 … A1,N
A2,1 A2,2 … A2,N

AN,1 AN,2 … AN,N

Output

If there exists no network that satisfies the condition, print -1. If it exists, print the shortest possible total length of the roads.

Example

Sample Input 1

3
0 1 3
1 0 2
3 2 0

Sample Output 1

3
The network below satisfies the condition:

City 1 and City 2 is connected by a road of length 1.
City 2 and City 3 is connected by a road of length 2.
City 3 and City 1 is not connected by a road.

Sample Input 2

3
0 1 3
1 0 1
3 1 0

Sample Output 2

-1
As there is a path of length 1 from City 1 to City 2 and City 2 to City 3, there is a path of length 2 from City 1 to City 3. However, according to the table, the shortest distance between City 1 and City 3 must be 3.

Thus, we conclude that there exists no network that satisfies the condition.

Sample Input 3

5
0 21 18 11 28
21 0 13 10 26
18 13 0 23 13
11 10 23 0 17
28 26 13 17 0

Sample Output 3

82

Sample Input 3

3
0 1000000000 1000000000
1000000000 0 1000000000
1000000000 1000000000 0

Sample Output 3

3000000000

题意:给出一具有 n 个点的图的邻接矩阵,求这个图的最短路的和,如果这个图的某个点不是最短点需要进行更新,则输出 -1

思路:跑 Floyd 即可,如需要更新,则输出 -1

Source Program

#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#define EPS 1e-9
#define PI acos(-1.0)
#define INF 0x3f3f3f3f
#define LL long long
const int MOD = 1E9+7;
const int N = 1000+5;
const int dx[] = {-1,1,0,0,-1,-1,1,1};
const int dy[] = {0,0,-1,1,-1,1,-1,1};
using namespace std;

LL G[N][N];
int main() {
    int n;
    scanf("%d",&n);
    for(int i=1;i<=n;i++)
        for(int j=1;j<=n;j++)
            scanf("%lld",&G[i][j]);

    bool flag=false;
    LL res=0;
    for(int i=1;i<=n&&!flag;i++){
        for(int j=i+1;j<=n&&!flag;j++){
            bool flag2=false;
            for(int k=1;k<=n&&!flag;k++){
                if(G[i][k]+G[k][j]

 

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