python字符串和文本

Python CookBook总结

用Shell 通配符匹配字符串

你想使用Unix Shell 中常用的通配符(比如.py , Dat[0-9].csv 等) 去匹配文
本字符串

>>> from fnmatch import fnmatch, fnmatchcase
>>> fnmatch('foo.txt', '*.txt')
True
>>> fnmatch('foo.txt', '?oo.txt')
True
>>> fnmatch('Dat45.csv', 'Dat[0-9]*')
True
>>> names = ['Dat1.csv', 'Dat2.csv', 'config.ini', 'foo.py']
>>> [name for name in names if fnmatch(name, 'Dat*.csv')]
['Dat1.csv', 'Dat2.csv']

fnmatch() 函数使用底层操作系统的大小写敏感规则(不同的系统是不一样的) 来
匹配模式。比如:

>>> # On OS X (Mac)
>>> fnmatch('foo.txt', '*.TXT')
False
>>> # On Windows
>>> fnmatch('foo.txt', '*.TXT')
True

字符串匹配和搜索

如果你想匹配的是字面字符串,那么你通常只需要调用基本字符串方法就行

>>> text = 'yeah, but no, but yeah, but no, but yeah'
>>> # Exact match
>>> text == 'yeah'
False
>>> # Match at start or end
>>> text.startswith('yeah')
True
>>> text.endswith('no')
False
>>> # Search for the location of the first occurrence
>>> text.find('no')
10

更复杂一些,需要使用正则表达式模块re

>>> text1 = '11/27/2012'
>>> import re
>>> re.match(r'\d+/\d+/\d+', text1):
>>> datepat = re.compile(r'\d+/\d+/\d+')
>>> datepat.match(text1)
>>> text = 'Today is 11/27/2012. PyCon starts 3/13/2013.'
>>> datepat.findall(text)
['11/27/2012', '3/13/2013']

字符串搜索和替换

对于简单的字面模式,直接使用str.repalce() 方法即可,比如:

>>> text = 'yeah, but no, but yeah, but no, but yeah'
>>> text.replace('yeah', 'yep')
'yep, but no, but yep, but no, but yep'

对于复杂的模式,请使用re 模块中的sub() 函数。为了说明这个,假设你想将形
式为11/27/2012 的日期字符串改成2012-11-27 。示例如下:

>>> text = 'Today is 11/27/2012. PyCon starts 3/13/2013.'
>>> import re
>>> re.sub(r'(\d+)/(\d+)/(\d+)', r'\3-\1-\2', text)
'Today is 2012-11-27. PyCon starts 2013-3-13.'
#如果你打算用相同的模式做多次替换,考虑先编译它来提升性能
>>> datepat = re.compile(r'(\d+)/(\d+)/(\d+)')
>>> datepat.sub(r'\3-\1-\2', text)
'Today is 2012-11-27. PyCon starts 2013-3-13.'
#对于更加复杂的替换,可以传递一个替换回调函数来代替
>>> from calendar import month_abbr
>>> def change_date(m):
... mon_name = month_abbr[int(m.group(1))]
... return '{} {} {}'.format(m.group(2), mon_name, m.group(3))
...
>>> datepat.sub(change_date, text)
'Today is 27 Nov 2012. PyCon starts 13 Mar 2013.'

如果除了替换后的结果外,你还想知道有多少替换发生了,可以使用re.subn()来代替。比如:

>>> newtext, n = datepat.subn(r'\3-\1-\2', text)
>>> newtext
'Today is 2012-11-27. PyCon starts 2013-3-13.'
>>> n
2

你需要以忽略大小写的方式搜索与替换文本字符串

>>> text = 'UPPER PYTHON, lower python, Mixed Python'
>>> re.findall('python', text, flags=re.IGNORECASE)
['PYTHON', 'python', 'Python']
>>> re.sub('python', 'snake', text, flags=re.IGNORECASE)
'UPPER snake, lower snake, Mixed snake'

最短匹配模式

#*是贪婪的,会尽可能多的匹配
>>> str_pat = re.compile(r'\"(.*)\"')
>>> text1 = 'Computer says "no."'
>>> str_pat.findall(text1)
['no.']
>>> text2 = 'Computer says "no." Phone says "yes."'
>>> str_pat.findall(text2)
['no." Phone says "yes.']
#?是不贪婪的,尽可能少的匹配
>>> str_pat = re.compile(r'\"(.*?)\"')
>>> str_pat.findall(text2)
['no.', 'yes.']

字符串对齐

#使用字符串的ljust() , rjust() 和center()方法
>>> text = 'Hello World'
>>> text.ljust(20)
'Hello World '
>>> text.rjust(20)
' Hello World'
>>> text.center(20)
' Hello World '
>>> text.rjust(20,'=')
'=========Hello World'
>>> text.center(20,'*')
'****Hello World*****'
#函数format() 同样可以用来很容易的对齐字符串。
#你要做的就是使用<,> 或者ˆ 字符后面紧跟一个指定的宽度。
>>> format(text, '>20')
' Hello World'
>>> format(text, '<20')
'Hello World '
>>> format(text, '^20')
' Hello World '
>>> format(text, '=>20s')
'=========Hello World'
>>> format(text, '*^20s')
'****Hello World*****'

以指定列宽格式化字符串

s = "Look into my eyes, look into my eyes, the eyes, the eyes, \
the eyes, not around the eyes, don't look around the eyes, \
look into my eyes, you're under."
>>> import textwrap
>>> print(textwrap.fill(s, 70))
Look into my eyes, look into my eyes, the eyes, the eyes, the eyes,
not around the eyes, don't look around the eyes, look into my eyes,
you're under.
>>> print(textwrap.fill(s, 40))
Look into my eyes, look into my eyes,
the eyes, the eyes, the eyes, not around
the eyes, don't look around the eyes,
look into my eyes, you're under.
>>> print(textwrap.fill(s, 40, initial_indent=' '))

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