模拟实现 strncpy

函数

strncpy有丢失 ‘\0’ 的危险

char* Strncpy(char* dest, const char* src, size_t n) {    
  assert(dest != NULL);                                                                                                                 
  assert(src != NULL);
  while (n) {    
  	if (*src == NULL) {
  		break;
  	}
    *dest++ = *src++;    
    --n;    
  }    
  return dest;    
}                  

测试

#include 
#include 
int main() {    
  char string1[256] = {0};    
  char string2[] = "I love you foever";    
  Strncpy(string1, string2, 6);    
  printf("%s\n", string1);    
  return 0;    
}    

效果图