【splay tree】 ZOJ 3765 Lights

简单的伸展树题。。。节点记录一下两种gcd状态即可。。。

#include <iostream>  
#include <queue>  
#include <stack>  
#include <map>  
#include <set>  
#include <bitset>  
#include <cstdio>  
#include <algorithm>  
#include <cstring>  
#include <climits>  
#include <cstdlib>
#include <cmath>
#include <time.h>
#define maxn 300005
#define maxm 400005
#define eps 1e-10
#define mod 1000000007  
#define lowbit(x) (x&(-x))  
#define ls o<<1
#define rs o<<1 | 1
#define lson o<<1, L, mid  
#define rson o<<1 | 1, mid+1, R  
typedef long long LL;
//typedef int LL;
using namespace std;

int gcd(int a, int b)
{
	if(!b) return a;
	else return gcd(b, a%b);
}
struct node
{
	int s, v, x, g[2];
	node *ch[2], *fa;
	int cmp(int x)
	{
		if(x == ch[0]->s + 1) return -1;
		if(x > ch[0]->s + 1) return 1;
		else return 0;
	}
	void maintain(void)
	{
		s = ch[0]->s + ch[1]->s + 1;
		g[0] = g[1] = 0;
		if(x) g[1] = gcd(g[1], v);
		else g[0] = gcd(g[0], v);
		g[0] = gcd(gcd(g[0], ch[0]->g[0]), ch[1]->g[0]);
		g[1] = gcd(gcd(g[1], ch[0]->g[1]), ch[1]->g[1]);
	}
}*null, *root, C[maxn], *top;
void rotate(node* &o, bool d)
{
	node *p = o->fa; p->ch[d^1] = o->ch[d], o->fa = p->fa;
	if(p->fa != null) {
		if(p->fa->ch[0] == p) p->fa->ch[0] = o;
		else p->fa->ch[1] = o;
	}
	if(p->ch[d^1] != null) p->ch[d^1]->fa = p;
	p->fa = o, o->ch[d] = p;
	p->maintain(), o->maintain();
}
void splay(node* &o, int k)
{
	int d = o->cmp(k);
	while(d != -1) {
		if(d == 1) {
			k -= o->ch[0]->s + 1;
			o = o->ch[1];
		}
		else o = o->ch[0];
		d = o->cmp(k);
	}
	node *p;
	while(o->fa != null) {
		p = o->fa;
		if(p->ch[0] == o) {
			if(p != null && p->fa->ch[0] == p)
				rotate(p, true);
			rotate(o, true);
		}
		else {
			if(p != null && p->fa->ch[1] == p)
				rotate(p, false);
			rotate(o, false);
		}
	}
}
node* merge(node *left, node *right)
{
	splay(left, left->s);
	left->ch[1] = right;
	right->fa = left;
	left->maintain();
	return left;
}
void split(node *o, int k, node* &left, node* &right)
{
	splay(o, k);
	right = o->ch[1];
	right->fa = null;
	o->ch[1] = null;
	left = o;
	left->maintain();
}
int n, m;
char s[20];

void init(void)
{
	top = C;
	null = top++;
	null->v = null->s = null->x = 0;
	null->g[0] = null->g[1] = 0;
	null->ch[0] = null->ch[1] = null->fa = NULL;
	root = top++;
	root->v = root->s = root->x = 0;
	root->ch[0] = root->ch[1] = null;
	root->maintain();
}
void build(void)
{
	node *p;
	int v, x;
	for(int i = 1; i <= n; i++) {
		scanf("%d%d", &v, &x);
		p = top++;
		p->v = v, p->x = x;
		p->ch[0] = root;
		p->ch[1] = p->fa = null;
		p->g[0] = p->g[1] = 0;
		root->fa = p;
		root = p;
		root->maintain();
	}
}
void work(void)
{
	int k, v, x, a, b;
	node *p, *mid, *left, *right;
	while(m--) {
		scanf("%s", s);
		if(s[0] == 'M') {
			scanf("%d%d", &k, &x);
			splay(root, k+1);
			root->v = x;
		}
		if(s[0] == 'R') {
			scanf("%d", &k);
			splay(root, k+1);
			root->x^=1;
		}
		if(s[0] == 'Q') {
			scanf("%d%d%d", &a, &b, &x);
			split(root, a, left, p);
			split(p, b-a+1, mid, right);
			if(mid->g[x] == 0) printf("-1\n");
			else printf("%d\n", mid->g[x]);
			root = merge(merge(left, mid), right);
		}
		if(s[0] == 'I') {
			scanf("%d%d%d", &k, &v, &x);
			mid = top++;
			mid->v = v, mid->x = x;
			mid->ch[0] = mid->ch[1] = mid->fa = null;
			mid->maintain();
			split(root, k+1, left, right);
			root = merge(merge(left, mid), right);
		}
		if(s[0] == 'D') {
			scanf("%d", &k);
			split(root, k, left, p);
			split(p, 1, mid, right);
			root = merge(left, right);
		}
	}
}
int main(void)
{
	while(scanf("%d%d", &n, &m)!=EOF) {
		init();
		build();
		work();
	}
	return 0;
}


你可能感兴趣的:(ZOJ)