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N-Queens
LeetCode
N-Queens
II
题目FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions. 和上一题类似,只需要求解解的数量,简化一下就可以了,具体见上一题。 代码:classSolution{ intans;//结果 vectorfrows,fcols,frowcol
xyzchenzd
·
2014-07-05 14:00
LeetCode
C++
算法
LeetCode
N-Queens
题目Then-queenspuzzleistheproblemofplacingnqueensonann×nchessboardsuchthatnotwoqueensattackeachother.Givenanintegern,returnalldistinctsolutionstothen-queenspuzzle.Eachsolutioncontainsadistinctboardconfi
xyzchenzd
·
2014-07-05 14:00
LeetCode
C++
算法
[leetcode]
N-Queens
II
insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.https://oj.leetcode.com/problems/n-queens-ii/思路:参考
N-Queens
jdflyfly
·
2014-06-26 11:00
java
LeetCode
backtracking
[leetcode]
N-Queens
Then-queenspuzzleistheproblemofplacingnqueensonann×nchessboardsuchthatnotwoqueensattackeachother.Givenanintegern,returnalldistinctsolutionstothen-queenspuzzle.Eachsolutioncontainsadistinctboardconfigu
jdflyfly
·
2014-06-26 11:00
java
LeetCode
backtracking
Leetcode:
N-Queens
II
思路,整个过程和前一题一样,最后返回结果vector的大小即可。(注意:冲突检测有更好的方法,比如对角线冲突就是abs(i-k)!=abs(board[i]-board[k]))其中board[i]表示第i个Queen放在第board[1]列。code:classSolution{ public: boolisAvailable(vector&board,intr,intc,intn){ for(
AIvin24
·
2014-06-24 10:00
LeetCode:
N-Queens
思路:经典的深度搜索题目,当前行尝试将Queen放在每列,如果和前面放好的Queen没有冲突,则开始下一行的搜索,否则,放到下一列,进行同样的冲突检测操作。code:classSolution{ public: boolisAvailable(vector&board,intr,intc,intn){//与放好的Queen进行冲突检测 for(inti=0;i=0&&j>=0){ if(board
AIvin24
·
2014-06-24 10:00
[LeetCode60]
N-Queens
II
FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.Analysis:Theideaissimilarwithlastquestions,thedifferentisnottorecordthesolutions,countthenum
sbitswc
·
2014-06-18 05:00
LeetCode
N皇后
[LeetCode59]
N-Queens
The n-queenspuzzleistheproblemofplacing n queensonan n×n chessboardsuchthatnotwoqueensattackeachother.Givenaninteger n,returnalldistinctsolutionstothe n-queenspuzzle.Eachsolutioncontainsadistinctboard
sbitswc
·
2014-06-18 05:00
LeetCode
N皇后
N-Queens
【leetcode】
N-queens
II
分析:详见
N-queens
实现:boolnextPermutation(vector&num) { inti=num.size()-1; while(i>=1) { if(num[i]>num[i-1]
shiquxinkong
·
2014-06-01 14:00
LeetCode
Algorithm
算法
面试题
【leetcode】
N-queens
问题:The n-queenspuzzleistheproblemofplacing n queensonan n×n chessboardsuchthatnotwoqueensattackeachother.Givenaninteger n,returnalldistinctsolutionstothe n-queenspuzzle.Eachsolutioncontainsadistinctbo
shiquxinkong
·
2014-06-01 14:00
Algorithm
LeetCode
算法
面试题
[leetcode]
N-Queens
II @ Python
原题地址:https://oj.leetcode.com/problems/n-queens-ii/ 题意:和
N-Queens
这道题其实是一样的,只不过这次要求返回的时N皇后的解的个数的问题。
·
2014-05-23 14:00
LeetCode
[leetcode]
N-Queens
@ Python
原题地址:https://oj.leetcode.com/problems/
n-queens
/ 题意:经典的N皇后问题。
·
2014-05-23 11:00
LeetCode
Permutations -- LeetCode
原题链接: http://oj.leetcode.com/problems/permutations/ 这道题跟
N-Queens
,SudokuSolver,CombinationSum,Combinations
linhuanmars
·
2014-03-20 00:00
java
LeetCode
算法
递归
NP
【LeetCode】
N-Queens
II N皇后问题 回溯法
N-QueensIITotalAccepted:4852TotalSubmissions:16065FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.Haveyoubeenaskedthisquestioninaninterview?
xiaozhuaixifu
·
2014-03-15 20:00
LeetCode
n皇后问题
Combinations -- LeetCode
原题链接: http://oj.leetcode.com/problems/combinations/ 这道题是NP问题的题目,时间复杂度没办法提高,用到的还是
N-Queens
中的方法:用一个循环递归处理子问题
linhuanmars
·
2014-03-15 00:00
java
LeetCode
算法
面试
递归
生成N皇后问题所有局面
N-Queens
Backtrackingisageneralalgorithmforfindingall(orsome)solutionstosomecomputationalproblem,thatincrementallybuildscandidatestothesolutions,andabandonseachpartialcandidatec("backtracks")assoonasitdetermin
luckyjoy521
·
2014-03-10 19:00
Combination Sum -- LeetCode
原题链接: http://oj.leetcode.com/problems/combination-sum/ 这个题是一个NP问题,方法仍然是
N-Queens
中介绍的套路。
linhuanmars
·
2014-03-10 03:00
java
LeetCode
算法
面试
递归
Sudoku Solver -- LeetCode
原题链接: http://oj.leetcode.com/problems/sudoku-solver/ 这道题的方法就是用在
N-Queens
中介绍的常见套路。
linhuanmars
·
2014-03-10 03:00
java
LeetCode
算法
面试
递归
N皇后问题的局面个数
N-Queens
II
对于N皇后问题,有多少种可能的局面呢?温习一下backtrack吧。代码:classSolution{ public: boolisValid(intboard[],intn,introw,intcol) { for(inti=0;i
luckyjoy521
·
2014-03-09 16:00
N-Queens
II -- LeetCode
原题链接: http://oj.leetcode.com/problems/n-queens-ii/ 这道题跟
N-Queens
算法是完全一样的,只是把输出从原来的结果集变为返回结果数量而已。
linhuanmars
·
2014-03-07 00:00
java
LeetCode
算法
面试
递归
N-Queens
-- LeetCode
原题链接: http://oj.leetcode.com/problems/
n-queens
/ N皇后问题是非常经典的问题了,记得当时搞竞赛第一道递归的题目就是N皇后。
linhuanmars
·
2014-03-07 00:00
java
LeetCode
算法
面试
递归
Leetcode
N-Queens
II
N-QueensII TotalAccepted: 4450 TotalSubmissions: 14913MySubmissionsFollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.递归回溯法的灵活运用。新思维:这里优化点是从底往上
kenden23
·
2014-03-06 07:00
LeetCode
II
N-Queens
LeetCode OJ:
N-Queens
II
N-QueensII FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.classSolution{ vectorrow,col,lslash,rslash; intresult; public: voiddfs(intdeep,in
starcuan
·
2014-01-29 13:00
LeetCode
DFS
LeetCode OJ:
N-Queens
N-Queens
The n-queenspuzzleistheproblemofplacing n queensonan n×n chessboardsuchthatnotwoqueensattackeachother.Givenaninteger
starcuan
·
2014-01-29 13:00
LeetCode
DFS
【LeetCode】
N-Queens
II && 【九度】题目1254:N皇后问题
10408MySubmissionsFollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.这个其实比
N-Queens
u013027996
·
2014-01-15 17:00
【LeetCode】
N-Queens
&& 【九度】题目1140:八皇后
N-Queens
TotalAccepted:3171TotalSubmissions:12620MySubmissionsThen-queenspuzzleistheproblemofplacingnqueensonann
u013027996
·
2014-01-15 16:00
Leetcode:
N-Queens
II
FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.用I的vector过不了,用数组速度应该会快一些,再加速一下同一列上是否合法的判断,过了。classSolution{ public: inttotalNQueens(intn){ i
u013166464
·
2014-01-11 22:00
LeetCode
[leetcode]
N-Queens
II
和I一样的。。。不过只输出可能数 感觉。。。可能有优化吧。。但是用I的代码过了。。。 class Solution { public: bool col[100]; bool d1[100]; // i + j bool d2[100]; // i - j + n int ans; void nque
·
2014-01-11 22:00
LeetCode
[leetcode]
N-Queens
八皇后,学递归入门题 判重复的技巧,就是对角线 x+y , x-y这样判断两个对角线了,把二维坐标压缩到一维,方便点。。 class Solution { public: bool col[100]; bool d1[100]; // i + j bool d2[100]; // i - j + n int cnt[100];
·
2014-01-11 22:00
LeetCode
Leetcode:
N-Queens
The n-queenspuzzleistheproblemofplacing n queensonan n×n chessboardsuchthatnotwoqueensattackeachother.Givenaninteger n,returnalldistinctsolutionstothe n-queenspuzzle.Eachsolutioncontainsadistinctboard
u013166464
·
2014-01-11 21:00
LeetCode
Leetcode
N-Queens
I
N-Queens
The n-queenspuzzleistheproblemofplacing n queensonan n×n chessboardsuchthatnotwoqueensattackeachother.Givenaninteger
kenden23
·
2013-12-20 08:00
LeetCode
I
N-Queens
LeetCode题解:
N-Queens
I and II
N-QueensThen-queenspuzzleistheproblemofplacingnqueensonann×nchessboardsuchthatnotwoqueensattackeachother.Givenanintegern,returnalldistinctsolutionstothen-queenspuzzle.Eachsolutioncontainsadistinctboar
MagiSu
·
2013-11-13 11:00
LeetCode
N-Queens
II N皇后问题(有几种放法)@LeetCode
是上一题的follow-up,问有总共几种方法。用全局变量易得,但是在java中不能像C++那么方便地用引用或指针传primitive参数。所以我觉得用returnvalue来记录方法数更好!packageLevel4; importjava.util.ArrayList; /** *N-QueensII * *FollowupforN-Queensproblem. * *Now,instea
hellobinfeng
·
2013-11-11 05:00
N-Queens
N皇后问题@LeetCode
packageLevel4; importjava.util.ArrayList; importjava.util.Arrays; /** * *
N-Queens
* *Then-queenspuzzleistheproblemofplacingnqueensonann
hellobinfeng
·
2013-11-11 04:00
Leetcode:
N-Queens
II
FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.方法一:我们继续用
N-Queens
doc_sgl
·
2013-10-19 23:00
LeetCode
bit
operation
N-Queens
Leetcode:
N-Queens
Then-queenspuzzleistheproblemofplacingnqueensonann×nchessboardsuchthatnotwoqueensattackeachother.Givenanintegern,returnalldistinctsolutionstothen-queenspuzzle.Eachsolutioncontainsadistinctboardconfigu
doc_sgl
·
2013-10-19 22:00
LeetCode
N
permutation
Queens
leetcode:
N-Queens
II (n皇后问题2)【面试算法题】
题目:FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.题意输出n×n的皇后棋子布局有多少种不同的情况。和上题一样的思路,只是不需要输出图,每次满足条件的时候记录一下次数。introw[1000]; intcol[1000]; int
zhang9801050
·
2013-09-29 17:00
leetcode:
N-Queens
(n皇后问题) 【面试算法题】
题目:The n-queenspuzzleistheproblemofplacing n queensonan n×n chessboardsuchthatnotwoqueensattackeachother.Givenaninteger n,returnalldistinctsolutionstothe n-queenspuzzle.Eachsolutioncontainsadistinctbo
zhang9801050
·
2013-09-29 16:00
LeetCode
N皇后
N-Queens
N-Queens
做这道题出了很多小问题:1、v[i][col[i]]=‘Q’写成了str[col[i]]=‘Q’,殊不知这样不会修改向量中的值2、回溯的时候,col.pop_back写成了push_backclassSolution{ public: vectorcol; vector>solveNQueens(intn){ //StarttypingyourC/C++solutionbelow //DONOTw
chen895281773
·
2013-09-15 00:00
[LeetCode] Anagrams、
N-Queens
Anagrams:Givenanarrayofstrings,returnallgroupsofstringsthatareanagrams.Note:Allinputswillbeinlower-case.比较Easy的题,用个map记录就是了。其实我可以说我没读懂题,百度人家的才懂吗。classSolution{ public: vectoranagrams(vector&strs){ //S
a83610312
·
2013-08-08 21:00
[leetcode刷题系列]
N-Queens
2
囧, 和上题基本上一样,没啥好说的classSolution{ conststaticintMAXN=100; boolcol[MAXN],add[MAXN],minus[MAXN]; intans[MAXN]; voiddfs(intnow,intn,int&ret){ if(now>=n){ ++ret; return; } for(inti=0;i
sigh1988
·
2013-08-04 00:00
[leetcode刷题系列]
N-Queens
经典题目了,递归搜索就行了classSolution{ conststaticintMAXN=100; boolcol[MAXN],add[MAXN],minus[MAXN]; intans[MAXN]; voiddfs(intnow,intn,vector>&ret){ if(now>=n){ vectorvs; for(inti=0;i>solveNQueens(intn){ //Startt
sigh1988
·
2013-08-04 00:00
N-Queens
TimeLimitExceeded,evenforsmalljudge.Iguessitisbecausethissolutionneedsn^2spacetostorestatusforeachQplacement.publicclassSolution{ ArrayListres; publicArrayListsolveNQueens(intn){ //StarttypingyourJav
violet_program
·
2013-06-05 05:00
【leetcode】
N-Queens
II
Question: FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.Anwser1: O(n^3) based-onRowclassSolution{ public: boolcheck(introw,int*colArray){
sunboy_2050
·
2013-04-13 11:00
【leetcode】
N-Queens
II
Question:FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.Anwser1:O(n^3)based-onRowclassSolution{ public: boolcheck(introw,int*colArray){ for
king_tt
·
2013-04-13 11:00
LeetCode
【leetcode】
N-Queens
Question:The n-queenspuzzleistheproblemofplacing n queensonan n*n chessboardsuchthatnotwoqueensattackeachother.Givenaninteger n,returnalldistinctsolutionstothe n-queenspuzzle.Eachsolutioncontainsadist
sunboy_2050
·
2013-04-13 10:00
【leetcode】
N-Queens
Question:Then-queenspuzzleistheproblemofplacingnqueensonann*nchessboardsuchthatnotwoqueensattackeachother.Givenanintegern,returnalldistinctsolutionstothen-queenspuzzle.Eachsolutioncontainsadistinctboa
king_tt
·
2013-04-13 10:00
LeetCode
leetcode 127:
N-Queens
II
N-QueensIIMar20'12FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.Agoodoptimizationexample:whentherequestresultissimplified,wemayusereducedd
xudli
·
2013-04-05 16:00
Leetcode 52
N-Queens
II
又练习了一下backtracking,算是一遍通过。几个注意的地方:1.使用了动态数组之后,注意memset一下清零(三个参数依次是:指针,要设置的值,长度)2.注意从第0个Queen开始放,这样便于理解和编程。3.注意isValid函数。一般在backtracking中,最好都有这样一个函数,便于程序的结构化。4.本次使用的是recursion,其实backtracking显然也可以通过iter
zxzxy1988
·
2013-02-14 14:00
LeetCode:
N-Queens
II
FollowupforN-Queensproblem.Now,insteadoutputtingboardconfigurations,returnthetotalnumberofdistinctsolutions.递归解法:classSolution{ public: boolcheck(introw,int*place) { for(inti=0;i
Tingmei
·
2012-10-09 00:00
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