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Sticks
Intel Compute
Sticks
电脑棒安装Ubuntu
IntelComputeSticks电脑棒安装Ubuntu前不久买了个二手的电脑棒(STCK1A32WFC),官方说可以装window1032bit或ubuntu64bit,刚开始为了方便就装了window做下载器,然而总是好卡,Wi-Fi也不稳定,就想着装个Ubuntu来试试情况。结果网上都没有中文的安装教程,只能找资料了,秉承我爱记录的习惯,就写个安装教程,供参考。1.下载准备1.1下载Ubu
宁静致远kioye
·
2018-08-05 11:02
Liunx
运维CentOS
其他硬件
ZOJ 1025 Wooden
Sticks
【思维 + 最长下降子序列 + Dilworth定理】
传送门//题意:有n个木头,每个木头有一个长度和重量.每次一根木头准备需要1分钟,如果下一根木头的(l’,w’)l’>=l,w’>=w,那么就不用多余准备时间,否则准备时间加1,问处理掉这些木头最少需要多少分钟.思路:有一个很明显的二维偏序关系在里面,那么假设我们只看一维,那么就是问最少可以划分多少组最长不下降子序列,那么由这个Dilworth定理我们可以转化为求这个序列的最长下降子序列,所以我们
Anxdada
·
2018-03-30 12:10
序列dp
Sticks
POJ - 1011(枚举+dfs)
Georgetooksticksofthesamelengthandcutthemrandomlyuntilallpartsbecameatmost50unitslong.Nowhewantstoreturnstickstotheoriginalstate,butheforgothowmanystickshehadoriginallyandhowlongtheywereoriginally.Ple
coldfresh
·
2018-03-20 17:17
DFS
Sticks
POJ - 1011(枚举+dfs)
Georgetooksticksofthesamelengthandcutthemrandomlyuntilallpartsbecameatmost50unitslong.Nowhewantstoreturnstickstotheoriginalstate,butheforgothowmanystickshehadoriginallyandhowlongtheywereoriginally.Ple
coldfresh
·
2018-03-20 17:17
DFS
HDU - 1051 Wooden
Sticks
贪心 动态规划
WoodenSticksTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):23527AcceptedSubmission(s):9551Thereisapileofnwoodensticks.Thelengthandweightofeachstickareknownin
ITryagain
·
2018-01-24 23:00
271
我则教他巧背筷子这个单词:把chopsticks分成chop(剁碎)十
sticks
(棍)来记然后,是和娃一起趣玩四大盆地、四大高原、三大平原的记法。
暖与希望
·
2017-12-27 21:11
matplotlib学习之图例,标注,透明度
np.linspace(-3,3,50)y1=2*x+1y2=x**2plt.figure()#setxlimitsplt.xlim((-1,2))plt.ylim((-2,3))#setnewsticksnew_
sticks
changzoe
·
2017-12-19 11:08
python
数据展现
Sticks
(dfs经典剪枝)
Georgetooksticksofthesamelengthandcutthemrandomlyuntilallpartsbecameatmost50unitslong.Nowhewantstoreturnstickstotheoriginalstate,butheforgothowmanystickshehadoriginallyandhowlongtheywereoriginally.Ple
七月初七小柠七
·
2017-12-08 17:36
暴力回溯
PC端的神器软件
2、桌面便签:小孩桌面便签,当时与
sticks
对比了一段时间后才决定用这个的。3、浏览器下载:IDM,非常好用,下载速度很快。4、电脑搜索:Everything。搜索东西非常快。
动感小麦兜
·
2017-11-22 21:58
经验
HD-ACM算法专攻系列(21)——Wooden
Sticks
题目描述:AC源码:此题考查贪心算法,解题思路:首先使用快速排序,以w或l按升序排序(注意相等时,应按另一值升序排序),这样就将二维变量比较,变为了一维的,排好序的一边就不需要去管了,只需要对未排序的一边直接进行贪心遍历。时间复杂度O(n^2)#include"iostream"#include"algorithm"usingnamespacestd;structStick{intl;intw;b
forcheng
·
2017-10-07 15:00
Sticks
POJ - 1011 (暴力dfs+剪枝)
Georgetooksticksofthesamelengthandcutthemrandomlyuntilallpartsbecameatmost50unitslong.Nowhewantstoreturnstickstotheoriginalstate,butheforgothowmanystickshehadoriginallyandhowlongtheywereoriginally.Ple
elbadaernu
·
2017-08-26 14:52
bfs&&dfs
贪心
POJ 1011
Sticks
(DFS+剪枝)详细注释
题目链接:http://poj.org/problem?id=1011SticksTimeLimit:1000MSMemoryLimit:10000KTotalSubmissions:147064Accepted:34847DescriptionGeorgetooksticksofthesamelengthandcutthemrandomlyuntilallpartsbecameatmost50u
码代码的小可爱
·
2017-08-07 15:25
搜索
百人工程1604期51号 Allen龙芊宇2017.07.18 打卡
在地上摆了鞋、用磁力棒做了门、用磁力棒代替
sticks
、没有鸡的玩偶用白色的小熊代替白色的母鸡,我刚摆放完Allen就开始唱着儿歌做儿歌里面相应的动作,我跟他玩了一遍之后之后他把他的玩偶恐龙、羊等玩偶都拿到拿了过来
红果ly
·
2017-07-18 23:50
POJ 1011--
Sticks
题意题目的大意呢是说有一堆长短不一的小棍,它们由原来若干根长度相同木棍截断而成,要求原来木棍的最短长度。分析这是一道比较典型的深度搜索题,原来的木棍长度最小可能是当前小棍里的最长值,所以先对小棍进行从大到小的排序,max(s1,s2,s3…sn)#includeusingnamespacestd;structStick{intLength;boolIsUsed;intNext;};boolComp
Hering_Linux
·
2017-07-06 23:26
C++/C
POJ解题报告
HDU1147 - Pick-up
sticks
- 计算几何(判断线段相交)
1.题目描述:Pick-upsticksTimeLimit:4000/2000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):3056AcceptedSubmission(s):1145ProblemDescriptionStanhasnsticksofvariouslength.Hethrowsthem
寒江雪里独钓着的蓑笠翁
·
2017-03-02 23:10
计算几何
Uva307
Sticks
【dfs+剪枝】【习题7-14】
题目:
Sticks
题意:起初有一些相等的木棍,然后被人砍成了n个木条。长度分别给出,现在需将n个木条组合拼成回原来的木棍,问原始木棍的最小可能长度?
GuoZLH
·
2017-02-19 22:00
ACM
uva
解题思路
[UVA]Wooden
Sticks
WoodenSticksDescriptionThereisapileofnwoodensticks.Thelengthandweightofeachstickareknowninadvance.Thesticksaretobeprocessedbyawoodworkingmachineinonebyonefashion.Itneedssometime,calledsetuptime,forthe
DSL_HN_2002
·
2017-01-28 12:09
文章类型——题解
Poj 1011-
Sticks
Poj1011-
Sticks
题意:有n根木棍(n#include#include#includeusingnamespacestd;constintN=70;inta[N],vis[N];intnum,
HopeForBetter
·
2016-12-15 21:15
ACM学习
题解
搜索
搜索
HDU 1501 Wooden
Sticks
(贪心算法)
WoodenSticksTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):18471AcceptedSubmission(s):7527ProblemDescriptionThereisapileofnwoodensticks.Thelengthandweightofe
Sitlos
·
2016-08-07 16:44
HDU
----贪心
poj1011
Sticks
DFS深度优先搜索+剪枝
这道题目吧,我看了蛮久的别人的博客,突然发现有一个剪枝,剪完之后从超时变成了0ms,太牛逼了。我的代码下面都有讲解,自己看看就OK了。闲话不多说,直接上代码:#include#include#include#include#include#includeusingnamespacestd;inta[70],n,len;//a是小棒的长度,n是有多少根,len是尝试len是否可以完成boolp[70
cnyali_ljf
·
2016-08-04 10:09
dfs
poj
poj1065 Wooden
Sticks
(没有交集元素的lis的条数)
题意:给你n个棍子,棍子有两个属性l和w,开启机器加工这些棍子,如果满足l1#include#include#includeusingnamespacestd;constintmaxn=5000;constintinf=0x3f3f3f3f;pairs[maxn+5];intn;inta[maxn+5];intg[maxn+5];intlis(){//最长上升子序列模板intans=0;memse
FightingForFinal
·
2016-07-30 18:52
动态规划
题解
ACM--木头序列--贪心+递减子序列--HDOJ 1051--Wooden
Sticks
HDOJ题目地址:传送门WoodenSticksTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):17453 AcceptedSubmission(s):7121ProblemDescriptionThereisapileofnwoodensticks.T
qq_26891045
·
2016-05-29 12:00
ACM
1051
贪心
hdoj
Wooden
Sticks
递减子序列
poj 1011
Sticks
(dfs+剪枝)
poj1011
Sticks
(dfs+剪枝)总时间限制:1000ms内存限制:65536kB描述Georgetooksticksofthesamelengthandcutthemrandomlyuntilallpartsbecameatmost50unitslong.Nowhewantstoreturnstickstotheoriginalstate
PKU_ZZY
·
2016-05-29 10:00
uva10003 Cutting
Sticks
题目链接题目大意一根长为len的木棍,上面有n个点需要切割,切割完之后有n+1根木棍。没切一根木棍时的费用等于木棍的长度,求最小的费用和。 思路记忆化搜索。solve(l,r)=min(solve(l,k)+solve(k,r))+a[r]-a[l]。l
KIJamesQi
·
2016-05-24 12:00
记忆化搜索
区间DP
poj2513 Colored
Sticks
(欧拉通路+Trie树+并查集)
D-ColoredSticksCrawlinginprocess...CrawlingfailedTimeLimit:5000MS MemoryLimit:128000KB 64bitIOFormat:%I64d&%I64uSubmitStatusPracticePOJ2513Appointdescription:SystemCrawler(2016-05-05)Description
su20145104009
·
2016-05-11 21:00
poj
Colored
Sticks
2513
欧拉通路+Trie树+并查集
poj2513
暴搜+回溯 ——
Sticks
SticksTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):8682 AcceptedSubmission(s):2561ProblemDescriptionGeorgetooksticksofthesamelengthandcutthemrandoml
yuan_jlj
·
2016-05-10 16:00
DFS
暴搜
UVa 10902 Pick-up
Sticks
(线段与线段相交)
题目:有n根木条,一根一根的往一个坐标系上丢(给出木条两点的坐标),问最后不被覆盖的木条有哪些,即丢的木条如果和前面丢的木条交叉的话,就会覆盖前面那根木条。公式:p1xp2=x1*y2-x2*y1(外积),p1*p2=(x1*x2,y1*y2)(内积)判断q是否在线段p1-p2上面,根据(p1-q)x(p2-q)=0来判断q是否在直线p1-p2上。利用内积(p1-q)*(p2-q) #includ
itaskyou
·
2016-05-09 22:00
uva
sti
Sticks
Pick-up
Pick-up
poj2653
Stic
10902Pick-up
线段与线段
uva 10003 Cutting
Sticks
题目:F - Cutting SticksTime Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %lluYou have to cut a wood stick into pieces. The most affordable company, The Analog Cutting Machinery, Inc. (ACM
a894383755
·
2016-05-09 08:00
动规
UVA_10902_Pick-up
Sticks
#include #include #include #include #include #include #include #include #include #include #include #pragmawarning(disable:4996) usingstd::cin; usingstd::cout; usingstd::endl; usingstd::stringstream; u
cxy7tv
·
2016-05-08 22:00
poj 2653 Pick-up
sticks
(计算几何)
Pick-upsticksTimeLimit: 3000MS MemoryLimit: 65536KTotalSubmissions: 11836 Accepted: 4475DescriptionStanhasnsticksofvariouslength.Hethrowsthemoneatatimeonthefloorinarandomway.Afterfinishingthrowing,Sta
clover_hxy
·
2016-05-07 10:00
UVA 10003 Cutting
Sticks
(区间 DP)
CuttingSticksTimeLimit:3000MS MemoryLimit:0KB 64bitIOFormat:%lld&%llu题目:题目大意:题目说的是有一根长为l的木棍,现在想要在其中n个位置切开,但是每次切都需要花费所切的棒子的长度的钱数,求最少话多少钱。刚开始拿到这道题,不知道怎么去解,想的是利用二分法的思想,没次取最靠近所切棍子中间的位置,但是,这样需要很大的
xia842655187
·
2016-05-06 21:00
dp
ACM
HDU
uva
AYITACM2016省赛第三周F - Cutting
Sticks
(切木头,区间电dp合并)
Youhavetocutawoodstickintopieces.Themostaffordablecompany,TheAnalogCuttingMachinery,Inc.(ACM),chargesmoneyaccordingtothelengthofthestickbeingcut.Theirprocedureofworkrequiresthattheyonlymakeonecutatatim
linyuxilu
·
2016-05-04 21:00
UVA 10003 Cutting
Sticks
区间dp
点击打开题目链接锯木头,一根长l的木头,有n个位置可以锯,每次锯的花费为当前木头的长度。求如何安排锯的顺序使得在n个位置锯后花费最小。区间dp。dp[L][R]表示合理安排锯的位置,从第L个位置距到第R个位置的最小花费。则dp[L][R]=min{dp[L][M]+dp[M+1][R]+a[R]-a[L-1],L #include #include #include usingnamespaces
Houheshuai
·
2016-05-03 09:00
dp
ACM
例题9-9 UVA 10003 Cutting
Sticks
切木棍(区间dp)
大体题意:给你一个长度为L的木棍,木棍上有n(n=j-1的话,直接return0;因为是记忆话搜索 所以如果d[i][j]如果不为-1的话 直接returnd[i][j]否则遍历i,j之间的东西!转移方程为: dp(i,k)+dp(k,j)+a[j]-a[i];更新d[i][j]即可!#include #include #include usingnamespacestd; intl,n; con
aozil_yang
·
2016-04-30 19:00
dp
C语言
Codeforces 525C Ilya and
Sticks
【数学】
题目链接:Codeforces525CIlyaandSticksC.IlyaandStickstimelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputIntheevening,afterthecontestIlyawasbored,andhereallyfeltlikem
chenzhenyu123456
·
2016-04-30 17:00
今日头条
问题二soeasy,直接把棍子排序,然后找最大的看最大的是否小于其他加和注意边界:棍子数
sticks
=newArrayList(); for(inti=0;i=sum){ System.out.println
zly9923218
·
2016-04-27 23:00
今日头条
hdu-1147 Pick-up
sticks
(判断线段相交)
题目链接:点击打开链接Pick-upsticksTimeLimit:4000/2000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):2680 AcceptedSubmission(s):978ProblemDescriptionStanhasnsticksofvariouslength.H
acm_cxq
·
2016-04-26 13:00
ACM
HDU
poj 10010
Sticks
bfs+减枝
题目:DescriptionGeorge took
sticks
of the same length and cut them randomly until all parts became at most
a894383755
·
2016-04-22 10:00
ACM
poj
bfs
UVA-307
Sticks
(搜索剪枝)
DescriptionGeorgetooksticksofthesamelengthandcutthemrandomlyuntilallpartsbecameatmost50unitslong.Nowhewantstoreturnstickstotheoriginalstate,butheforgothowmanystickshehadoriginallyandhowlongtheywereori
bmamb
·
2016-04-21 10:00
(Java实现) HDOJ 1051 Wooden
Sticks
贪心算法
ProblemDescription(a)第一根木材的安装时间是1分钟(b)在处理完长度为l,宽度为w的木材后,若紧接着处理的木材长度l'>l且w'>w,则不需要安装时间,否则需1分钟安装时间(c)找出最短安装时间的序列对解决思路:1.根据木材数n创建对应的n个木材对象,初始化其长度和宽度2.将所有木材以长度升序排列(当长度相等时,宽度宽的排在后面)3.调整机器安装时间(time++),处理排列后
why_still_confused
·
2016-04-19 23:00
java
HDU
贪心算法
ACM刷题之HDU————Wooden
Sticks
WoodenSticksTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):17181 AcceptedSubmission(s):7010ProblemDescriptionThereisapileofnwoodensticks.Thelengthandw
xiaofeng187
·
2016-04-13 13:00
算法
ACM
杭电
poj 2653 Pick-up
sticks
Stanhasnsticksofvariouslength.Hethrowsthemoneatatimeonthefloorinarandomway.Afterfinishingthrowing,Stantriestofindthetopsticks,thatisthesestickssuchthatthereisnostickontopofthem.Stanhasnoticedthatthela
dd_lucky
·
2016-04-12 21:00
poj 1065 Wooden
Sticks
WoodenSticksTimeLimit: 1000MS MemoryLimit: 10000KTotalSubmissions: 20948 Accepted: 8875DescriptionThereisapileofnwoodensticks.Thelengthandweightofeachstickareknowninadvance.Thesticksaretobeprocessedby
LeeHolmes
·
2016-04-11 21:00
poj
贪心
POJ-2513 Colored
Sticks
TimeLimit:5000MS MemoryLimit:128000KTotalSubmissions:34372 Accepted:8976DescriptionYouaregivenabunchofwoodensticks.Eachendpointofeachstickiscoloredwithsomecolor.Isitpossibletoalignthesticksinastraight
u014258433
·
2016-04-07 21:00
ACM
字典树
好题
POJ 2513 Colored
Sticks
(hash + 欧拉道路)
题目链接:点击打开链接题意:n个木棍,两端有颜色,相同颜色可以链接,问你最终能否形成一条线段。思路:典型的欧拉道路,成立的条件是1.图联通。2.度为奇数的点不能超过2个。用map超时了,可以用hash水过去。细节参见代码:#include #include #include #include #include #include #include #include #include #include
weizhuwyzc000
·
2016-04-05 22:00
hash
poj
ACM-ICPC
欧拉道路
poj-2452
Sticks
Problem(二分+RMQ)
SticksProblemTimeLimit: 6000MS MemoryLimit: 65536KTotalSubmissions: 10299 Accepted: 2729DescriptionXuanxuanhasnsticksofdifferentlength.Oneday,sheputsallhersticksinaline,representedbyS1,S2,S3,...Sn.Aft
acm_cxq
·
2016-04-01 16:00
ACM
HDU
hdu1051Wooden
Sticks
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1051简简单单的贪心,竟然错了好几次。。。思路:先排序,按照长度升序,或者重量升序,在查找。。代码:#include #include #include usingnamespacestd; typedefstruct { intlength; intweight; }stick; sticka[
wsn564533648
·
2016-03-27 20:00
ACM
贪心
POJ 1011
Sticks
木棒
原题链接题意:右上角Language简体中文,拿好不谢分析:主要算法STMD算法(搜索)+剪枝详细方法枚举ANS(Answer),搜索能否完成。能够完成直接输出结果下个Case,否则继续搜索下个ANS此题重点在于剪枝,剪枝很重要,先给出几个剪枝方法:1ANS必须是SUM(所有木棍长度和)的约数,否则一定拼不成若干个ANS,这是显而易见的。 2正在拼凑某一长度木棍时,如果发现当前尝试的小棒无法胜任
YOUSIKI
·
2016-03-27 11:00
UVA 307(p218)----
Sticks
#include #include #include #include #definedebu usingnamespacestd; constintmaxn=1e7; intn,l,sum; inta[maxn]; intv[maxn]; intcmp(inta,intb) { returna>b; } intdfs(intlen,intnum,intpos) { if(l*num==sum)r
wang2147483647
·
2016-03-26 19:00
练习一1008
There is a pile of n wooden
sticks
. The length and weight of each stick are known in advance.
baidu_34275752
·
2016-03-25 16:00
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