eight

[水晶报表]金额转英文大写

，Crystal语法localstringVararraysmallNumbers:=["ZERO","ONE","TWO","THREE","FOUR","FIVE","SIX","SEVEN","EIGHT
厦门德仔·2015-08-17 14:26

[水晶报表]金额转英文大写

Crystal语法 localstringVararraysmallNumbers:=["ZERO","ONE","TWO","THREE","FOUR","FIVE","SIX","SEVEN","EIGHT
david_520042·2015-08-17 14:00

HDU-1043 Eight（A*）

EightTimeLimit:10000/5000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):15894    AcceptedSubmission(s):4386SpecialJudgeProblemDescriptionThe15-puzzlehasbeenaroundforover100
idealism_xxm·2015-08-10 20:00

.NET PDF转图片

O2S.Components.PDFRender4NET.dllImportsO2S.Components.PDFRender4NETPublicEnumDefinition One=1 Two=2 Three=3 Four=4 Five=5 Six=6 Seven=7 Eight
u013162930·2015-08-07 13:00

【双向BFS搜索】hdu3567Eight II

http://acm.hdu.edu.cn/showproblem.php?pid=3567题目大意：8数码问题。给定起始状态和目标状态，求最少移动次数和字典序最小的方案。（r：向右，l：向左，u：向上，d：向下）用单向BFS–>无限TLE可以用双向BFS和A∗搜索，但注意由于要求字典序最小，无论是双向BFS，还是A∗搜索都无法保证最先出现的解字典序最小。无奈只得将最小移动次数全都搜索一次。据说双
cqbztsy·2015-07-29 22:00

八皇后问题

//eight_queen.cpp:定义控制台应用程序的入口点。
u014568921·2015-07-29 02:00

【启发式搜索】[POJ 1077]Eight

八数码问题，用的A*解决，但是数据太强A不了。。。TLE只能在POJ上先过一发了。#include #include #include #include #include #include #include #include #include usingnamespacestd; constintMAXVIS=500000; structState{ unsignedshorts[9]; inth
JeremyGJY·2015-07-23 15:00

Divisibility by Eight

把当前数删除几位然后可以整除与8那么可得知大于3位数的判断是否能整除于八的条件是(n%1000)%8==0可以得出我们的结论：只需要枚举后三位后两位后一位即可知道是否可整除于8#include #include #include usingnamespacestd; chara[200]; intmain(){ //printf("%d\n",344%8); intans=0; intflag=0
u013076044·2015-07-20 20:00

XJTU Summer Holiday Test 1(Divisibility by Eight-8的倍数)

C- DivisibilitybyEightTimeLimit:2000MS     MemoryLimit:262144KB     64bitIOFormat:%I64d&%I64uSubmit StatusDescriptionYouaregivenanon-negativeinteger n,itsdecimalrepresentationconsistsofatmost 100 digi
nike0good·2015-07-12 17:00

Eight(South Central USA 1998)

DescriptionThe15-puzzlehasbeenaroundforover100years;evenifyoudon'tknowitbythatname,you'veseenit.Itisconstructedwith15slidingtiles,eachwithanumberfrom1to15onit,andallpackedintoa4by4framewithonetilemiss
Forever_wjs·2015-07-09 20:00

Eight(South Central USA 1998)（八数码） 分类： bfs 2015-07-05 22:34 1人阅读 评论(0) 收藏

The 15-puzzle has been around for over 100 years; even if you don’t know it by that name, you’ve seen it. It is constructed with 15 sliding tiles, each with a number from 1 to 15 on it, and all packed
·2015-07-05 22:00

python实现将英文单词表示的数字转换成阿拉伯数字的方法

具体实现方法如下：importre_known={'zero':0,'one':1,'two':2,'three':3,'four':4,'five':5,'six':6,'seven':7,'eight
秋风秋雨·2015-07-02 14:35

[CodeForces550C]Divisibility by Eight[数学]

题目链接：[CodeForces550C]DivisibilitybyEight[数学]题意分析：给出一个长度不超过100的数字，我们可以删除其中的多个数字，但是不能改变顺序。然后得到一个开头不能为0的数字，如果该数字能被8整除，就输出它。如果无法得到这种数字，就输出NO。解题思路：8*125=1000。这是个非常神奇的事情，这意味着，当数字长度大于4位时，我们只要判断前3位能否被8整除即可判断该
CatGlory·2015-06-27 20:00

CodeForces 550C Divisibility by Eight(枚举)

【题目链接】clickhere~~【题目大意】给一个不超过100位的数字，要求能否删掉几位数，剩下的数能被8整除【解题思路】：这里有个性质：如果一个数后三位能被8整除，那么这个数就能被8整除证明：举一个5位数的例子吧，例如_____ _____ __       __ __        __ ___abcde=ab000+cde=1000×ab+cde=8×125×ab+cde很明显，8×125
u013050857·2015-06-27 11:00

550C Divisibility by Eight(还是枚举)

给一个大数，问能否删除其中若干位使得其能够被8整除首先要知道：一个数如果后三位能够被8整除，则其能够被8整除。预先找出1000以内的能被8整除的数。然后对于这每一个数，看能否在所给的大数中找到对应位的数字（注意顺序）即可#-*-coding:utf-8-*- s=raw_input() sl=len(s) a=xrange(0,1000,8) l=len(a) ans=-1 foriinxrang
u014679804·2015-06-26 19:00

Codeforces Round #299 (Div. 2) A. Tavas and Nafas

usingnamespacestd; intmain() { strings1[10]={"zero","one","two","three","four","five","six","seven","eight
qingshui23·2015-06-24 14:00

时差8小时的解决方法

import datetime eight_hour = datetime.timedelta(hours=8) (organization_file.upload_date + eight_hour)
tavenpy·2015-06-15 17:00

隐马尔科夫八

出处：http://www.52nlp.cn/hmm-learn-best-practices-eight-summary八、总结(Summary)通常，模式并不是单独的出现，而是作为时间序列中的一个部分
weilianyishi·2015-06-09 21:00

Codeforces550C:Divisibility by Eight

Youaregivenanon-negativeinteger n,itsdecimalrepresentationconsistsofatmost 100 digitsanddoesn'tcontainleadingzeroes.Yourtaskistodetermineifitispossibleinthiscasetoremovesomeofthedigits(possiblynotremo
libin56842·2015-06-09 15:00

Over the past eight years

NFLPreseasonHomeUnderdogsNFLPreseasonUnderdogsThisisoursecondarticledealingwiththeNFLpreseasonanditwon'tbethelast.Thefirstarticle,writtenseveralyearsagodealtwiththingslikequarterbackrotationsandcoache
lluggg853·2015-06-02 13:00

HDU1228 A+B 字符串模拟题

include usingnamespacestd; charnum[10][10]={"zero","one","two","three","four","five","six","seven","eight
AC_Gibson·2015-05-22 10:00

java eight_queue

publicclassTest{publicvoidcalmaze(int[][]pmaze,intnlvl){for(inti=0;i0&&tmpcol>0){if(pmaze[tmprow-1][tmpcol-1]==1){returnflag;}tmprow--;tmpcol--;}tmprow=row;tmpcol=col;while(tmprow>0&&tmpcol0){if(pmaze
小牛快跑he·2015-05-08 14:25

java eight_queue

publicclassTest{publicvoidcalmaze(int[][]pmaze,intnlvl){for(inti=0;i0&&tmpcol>0){if(pmaze[tmprow-1][tmpcol-1]==1){returnflag;}tmprow--;tmpcol--;}tmprow=row;tmpcol=col;while(tmprow>0&&tmpcol0){if(pmaze
小牛快跑he·2015-05-08 14:25

HDU 1228 A + B 字符串操作(常规 & hash)

include usingnamespacestd; charary[11][10]={"zero","one","two","three","four","five","six","seven","eight
xinwen1995·2015-04-19 08:00

BZOJ 3128 Usaco2013 Open Figure Eight

题目大意：给定一个有坏点的矩阵，求能画出来的最大的“8”字形“8”字形满足：*数字8由上下两个矩形构成。*数字8的上下两个矩形都满足至少有一个单元格在矩形内部。*数字8顶部的矩形的底边必须为底部矩形顶边的子集。*数字8只能刻在大理石完美无瑕的部分。*规定数字8的得分为上矩形和下矩形的面积的乘积，它们希望得分能达到最大。枚举顶部矩形的底边，可以用上一行的底边O(1)转移得到，然后每行O(n^2)向左
PoPoQQQ·2015-04-14 18:00

HDU 1043 Eight

ProblemDescriptionThe15-puzzlehasbeenaroundforover100years;evenifyoudon'tknowitbythatname,you'veseenit.Itisconstructedwith15slidingtiles,eachwithanumberfrom1to15onit,andallpackedintoa4by4framewithonet
jtjy568805874·2015-04-01 17:00

JavaScript语言精粹【数组、正则表达、JSON、JSLint】

数组：varnumbers=['zero','one','two','three','four','five','six','seven','eight','nine'];对象字面量：varnumbers_object
ligang2585116·2015-03-28 15:00

hud 1043 Eight

EightTimeLimit:10000/5000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):14009    AcceptedSubmission(s):3965SpecialJudgeProblemDescriptionThe15-puzzlehasbeenaroundforover100
wust_ZJX·2015-03-27 20:00

UVALIVE 6301 The Shortcut Eight-Puzzle

 思路：使用A*算法的搜索#include #include #include #include #include #include #include #include #include #include #include #include #defineLLlonglong #defineu64unsignedlonglong #definemaxn50010 #d
_log__·2015-03-20 23:00

Eight queens 算法及实现

C语言实现：#include   int chess[8][8]={0};   int a[8],b[15],c[15];   int sum=0;//add all method   void PutQueen(int n)   {       int col,i,j;       for(col=0;col<8;col++)       {           if(a[col]&& b[n
听那水·2015-03-20 21:00

实现百度搜索栏自动提示功能

.ready(function(){$('#down').AutoComplete({'data':['One','Two','Three','Four','Five','Six','Seven','Eight
843977358·2015-03-19 14:00

实现百度搜索栏自动提示功能

.ready(function(){$('#down').AutoComplete({'data':['One','Two','Three','Four','Five','Six','Seven','Eight
843977358·2015-03-19 14:00

运行nltk示例 Resource u'tokenizers punkt english.pickle' not found解决

Resource u'tokenizers/punkt/english.pickle' not found错误 import nltk sentence = """At eight
·2015-03-18 17:00

nltk的简单应用

utf-8 -*- """ http://www.nltk.org/ 首页示例 """ import nltk # Tokenize and tag some text: sentence = "At eight
Nob·2015-03-09 19:00

HDU1043:Eight HDU3567:Eight II(康拓展开+bfs搜索）

HDU1043:Eight这个题还算好过，用我刚整理的康拓展开的模板直接就ok的，需要注意的是对于这种终态唯一的题目，一般用终态来反搜初态，就是一边bfs记录下所有答案，如此如此，看下AC程序的主函数就能理解的
u014569598·2015-03-07 00:00

超能陆战队：迪士尼画风的漫威英雄

  http://www.hjenglish.com/new/p718262/My little friend Seth, who is eight, pronounces this the
·2015-02-25 19:00

hdu 1034 & poj 1077 Eight 传说中的八数码问题。真是一道神题，A*算法+康托展开

EightTimeLimit:10000/5000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):13506    AcceptedSubmission(s):3855SpecialJudgeProblemDescriptionThe15-puzzlehasbeenaroundforover100
Lionel_D·2015-02-15 00:00

英语入门第一单元课题3和课题4

课题导图.png课题3：询问电话号码本节课会用到的词汇词汇翻译zero0one1two2three3four4five5six6seven7eight8nine9ten10对于发音的部分还不能够很好的解决在手机端上
学习那点事·2015-02-04 21:37

POJ_1077_Eight（八数码）

题目就不粘贴了。说的就是八数码的问题，纠结了好几天了，一开始用map去做，然后TLE到让人呕吐；今天做的时候用到了康托展开，但是还是TLE，这就让人有点不愉快了，可是尼玛还是一直TLE啊！神啊！救命啊~~~纠结了一会后，把题目中所有的string全部换成char，诶，尼玛居然就过了！我就呵呵了......由此得出一个结论：stl能不用就尽量不用，尽管它很方便，简洁。有关于康托展开的内容，请戳：ht
jhgkjhg_ugtdk77·2014-12-30 22:00

HDU 1043 Eight

题目链接：Eight解题思路：原来不知道，这是有名的8数码问题，它还用和15数码来废话半天。看了眼过的人数，直接BFS肯定就T了，况且，状态总数是9！
u010787640·2014-12-19 16:00

swift尾随闭包

    0: "Zero", 1: "One", 2: "Two",   3: "Three", 4: "Four",     5: "Five", 6: "Six", 7: "Seven", 8: "Eight
itfanr·2014-12-15 19:00

SequenceFile与MapFile

publicstaticStringuri="hdfs://192.168.1.201:9100";publicstaticString[]data={"one,two","three,four","five,six","seven,eight
deyu1982·2014-12-10 16:37

隐马尔可夫模型（HMM）攻略

http://www.52nlp.cn/hmm-learn-best-practices-eight-summaryhttp://blog.csdn.net/likelet/article/details
crazyjiang·2014-12-09 16:00

JavaScript 编写的简易计算器

var one="1"; var two="2"; var three="3"; var four="4"; var five="5"; var six="6"; var seven="7"; var eight
期待变强的菜鸟·2014-11-24 16:00

最全的 CSS2.1 和 CSS3+ 的区别一览

  animation (and eight associated lo
fengbin2005·2014-11-14 21:00

JQuery和javascript优秀插件收集

ynif.v099.10000net.cn/demo/shijian/3/shijian/index.html 别人收集信息 8个实用的页面布局和用户界面jQuery插件http://blog.ui90.com/eight-practical-jquery-plugin-page-layout
jackrenming·2014-11-01 12:00

YII 显示代码执行时间

*/ functionactionTime(){ //查看脚本开始时间 Yii::beginProfile('mytime'); for($i=0;$i"; elseif($i%8==0) echo"eight
buyingfei888·2014-10-27 14:00

Lambda表达式练习

static string[] strings = new string[] { "zero", "one", "two", "three", "four", "five", "six", "seven", "eight
caocg504·2014-10-24 16:50

HDU 搜索进阶专题

HDU搜索进阶专题去年听ReDow讲A*,IDA*，当时小菜（现在也是），就没把那些东西列在学习范围内，前些天LCY让我讲搜索进阶，就做了几题，分享下做题感受～～   HDU1043 Eight涉及到人生完不完整的一道题
·2014-09-30 10:00

事务Url

http://www.infoq.com/cn/articles/eight-isolation-levels http://blog.sina.com.cn/s/blog_6ac4c6cb010186cn.html
dk05408·2014-09-23 09:00
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