[Leetcode][python]Reorder List/重排链表

题目大意

将单向链表L0→L1→…→Ln-1→Ln转化为L0→Ln→L1→Ln-1→L2→Ln-2→…的形式，也就是从头部取一个节点，从尾部取一个节点，直到将原链表转化成新的链表。

解题思路

1. 去中间节点，将链表分为两段.
2. 翻转后一段
3. 拼接

代码

class Solution:
    def reorderList(self, head):
        """
        :type head: ListNode
        :rtype: void Do not return anything, modify head in-place instead.
        """
        if not head:
            return
        # split {1,2,3,4,5} to {1,2,3}{4,5}
        fast = slow = head 
        while fast and fast.next:
            slow = slow.next
            fast = fast.next.next
        head1 = head
        head2 = slow.next
        slow.next = None
        # reverse the second {4,5} to {5,4}
        cur, pre = head2, None
        while cur:
            nex = cur.next
            cur.next = pre
            pre = cur
            cur = nex
        # merge
        cur1, cur2 = head1, pre
        while cur2:
            nex1, nex2 = cur1.next, cur2.next
            cur1.next = cur2
            cur2.next = nex1
            cur1, cur2 = nex1, nex2

总结