Alice and Bob 数学题

Problem F:Alice and Bob

Time Limit: 1000/1000ms (Java/Other)   Memory Limit : 65535/32768K(Java/Other)

 

ProblemDescription

Alice andBob like playing games very much.Today, they introduce a new game.

There isa polynomial like this: (a₀*x^(2^0)+1) * (a₁ *x^(2^1)+1)*.......*(a_n-1 * x^(2^(n-1))+1). Then Alice ask Bob Qquestions. In the expansion of the Polynomial, Given aninteger P, please tell the coefficient of the x^P.

Can you help Bob answer these questions?

 Input

The first line of the input is a number T, which means the number ofthe test cases.

For each case, the first line contains a number n, then n numbers a₀,a₁, .... a_n-1 followed in the next line. In the thirdline is a number Q, and then following Q numbers P.

1 <= T <= 20

1 <= n <= 50

0 <= a_i <= 100

Q <= 1000

0 <= P <= 1234567898765432

 Output

For each question of each test case, pleaseoutput the answer module 2012.

 Sample Input

1

2

2 1

2

3

4

 Sample Output

2

0

 Hint

The expansion of the (2*x^(2^0) + 1) *(1*x^(2^1) + 1) is 1 + 2*x^1 + 1*x^2 + 2*x^3

#include
#include
#include
#include
#include
#include
using namespace std;
const int mod=2012;
long long p;
int que;
int a[55];
int main()
{

     freopen("in.in","r",stdin);
     int T;
     scanf("%d",&T);
     while(T--)
     {
         int n;
         scanf("%d",&n);
         for(int i=1;i<=n;i++)
            scanf("%d",&a[i]);
         a[n+1]=0;
         scanf("%d",&que);
         while(que--)
         {
             cin>>p;
             int ans=1;
             int st=1;
             while(p)
             {
                if(p&1) ans=(ans*a[st])%mod;
                 p/=2;st++;
                 if(st>n+1) break;
             }
             cout<