Codeforces Round #357 (Div. 2)-B. Economy Game

原题链接

暴力枚举1234567和123456的系数

#include 
#define INF 1e9
using namespace std;
typedef long long ll;

int main(){
	
	int n;
	
	cin >> n;
	for(ll i = 0; i * 1234567 <= n; i++)
	   for(ll j = 0; j * 123456  + i * 1234567 <= n; j++){
	   	  
	   	  int d = n - i * 1234567 - j * 123456;
	   	  if(d % 1234 == 0){
	   	    cout << "YES" << endl;
	   	    return 0;
	   	  }
	   }
	cout << "NO" << endl;
	return 0;
}

B. Economy Game

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he was entertained by the testing so much, that he found out his game-coin score become equal to 0.

Kolya remembers that at the beginning of the game his game-coin score was equal to n and that he have bought only some houses (for1 234 567 game-coins each), cars (for 123 456 game-coins each) and computers (for 1 234 game-coins each).

Kolya is now interested, whether he could have spent all of his initial n game-coins buying only houses, cars and computers or there is a bug in the game. Formally, is there a triple of non-negative integers a, b and c such thata × 1 234 567 + b × 123 456 + c × 1 234 = n?

Please help Kolya answer this question.

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 109) — Kolya's initial game-coin score.

Output

Print "YES" (without quotes) if it's possible that Kolya spent all of his initial n coins buying only houses, cars and computers. Otherwise print "NO" (without quotes).

Examples

input

1359257

output

YES

input

17851817

output

NO

Note

In the first sample, one of the possible solutions is to buy one house, one car and one computer, spending1 234 567 + 123 456 + 1234 = 1 359 257 game-coins in total.