JPA学习笔记五 单向多对一

建表语句,虽然可以自动建表,但我就是想皮一下,开心

CREATE TABLE t_user (
    id INT NOT NULL auto_increment,
    `name` VARCHAR (20),
    PRIMARY KEY (id)
) ENGINE = INNODB DEFAULT charset = utf8;

CREATE TABLE t_orders (
    id INT NOT NULL auto_increment,
    `name` VARCHAR (20),
    uid INT,
    PRIMARY KEY (id),
    CONSTRAINT t_user_id FOREIGN KEY (uid) REFERENCES t_user (id)
) ENGINE = INNODB DEFAULT CHARSET = utf8;


persistence.xml文件



    

        
        org.hibernate.ejb.HibernatePersistence

        
        com.yjj.entity.Order
        com.yjj.entity.User

        
            
            
            
            
            

            
            
             
            
        
    

实体类
一的一方表中就只有id和name,那么属性也就只有id和name

package com.yjj.entity;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;
/**
 * 单向多对一
 * t_user表字段,id,name
 */
@Table(name = "t_user")
@Entity
public class User {
    @Id
    @GeneratedValue
    private Integer id;

    private String name;

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @Override
    public String toString() {
        return "User{" +
                "id=" + id +
                ", name='" + name + '\'' +
                '}';
    }
}


多的一方表中有id,name,uid(外键对应t_user表的id),那么属性就有id,name,把uid换成对应的实体类User,维护一个User对象

package com.yjj.entity;

import javax.persistence.*;
/**
 * 单向多对一
 * t_orders表字段,id,name,uid
 */
@Table(name = "t_orders")
@Entity
public class Order {
    @Id
    @GeneratedValue
    private Integer id;
    private String name;
    @JoinColumn(name = "uid")
    @ManyToOne
    private User user;

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public User getUser() {
        return user;
    }

    public void setUser(User user) {
        this.user = user;
    }

    @Override
    public String toString() {
        return "Order{" +
                "id=" + id +
                ", name='" + name + '\'' +
                ", user=" + user +
                '}';
    }
}


测试类

      User user =new User();
        user.setName("殷俊杰");
        Order order=new Order();
        order.setName("订单一");
        order.setUser(user);
        Order order1=new Order();
        order1.setName("订单二");
        order1.setUser(user);

        manager.persist(user);
        manager.persist(order);
        manager.persist(order1);
        

输出

Hibernate: 
    insert 
    into
        t_user
        (name) 
    values
        (?)
Hibernate: 
    insert 
    into
        t_orders
        (name, uid) 
    values
        (?, ?)
Hibernate: 
    insert 
    into
        t_orders
        (name, uid) 
    values
        (?, ?)

单向多对一保存的时候必须先保存一方,否则会出现多余的update语句,从而影响性能
试一下先保存多的一方,再保存一的一方

        manager.persist(order);
        manager.persist(order1);
        manager.persist(user);

输出

Hibernate: 
    insert 
    into
        t_orders
        (name, uid) 
    values
        (?, ?)
Hibernate: 
    insert 
    into
        t_orders
        (name, uid) 
    values
        (?, ?)
Hibernate: 
    insert 
    into
        t_user
        (name) 
    values
        (?)
Hibernate: 
    update
        t_orders 
    set
        name=?,
        uid=? 
    where
        id=?
Hibernate: 
    update
        t_orders 
    set
        name=?,
        uid=? 
    where
        id=?

结论:如果先插入order,它的USER_ID字段会先为空,在插入user之后,再进行update操作,USER_ID。因此,在多对一映射关系的情况下,建议先插入“一”的对象(user),再插入“多”的对象(order),减少sql语句可以提高效率
查找

        Order order=manager.find(Order.class,1);
        System.out.println(order);

输出

Hibernate: 
    select
        order0_.id as id1_1_0_,
        order0_.name as name2_1_0_,
        order0_.uid as uid3_1_0_,
        user1_.id as id1_3_1_,
        user1_.name as name2_3_1_ 
    from
        t_orders order0_ 
    left outer join
        t_user user1_ 
            on order0_.uid=user1_.id 
    where
        order0_.id=?
Order{id=1, name='订单一', user=User{id=1, name='殷俊杰'}}

@ManyToOne(fetch=FetchType.LAZY)在ManyToOne注解中可加入FetchType.LAZY延迟加载,在用到一的对象时才真正查询一的对象
删除

 Order order=entityManager.find(Order.class,1);
 entityManager.remove(order);

输出

Hibernate: 
    select
        order0_.id as id1_0_0_,
        order0_.ordername as ordernam2_0_0_,
        order0_.userid as userid3_0_0_,
        user1_.id as id1_3_1_,
        user1_.name as name2_3_1_ 
    from
        t_order order0_ 
    left outer join
        user user1_ 
            on order0_.userid=user1_.id 
    where
        order0_.id=?
Hibernate: 
    delete 
    from
        t_order 
    where
        id=?

不会关联删除user因为还有其他订单关联着user,如果先删除user的话会报错,因为外键关联。
更新

 Order order=entityManager.find(Order.class,2);
 order.getUser().setName("霸波尔奔");
 transaction.commit();

输出

Hibernate: 
    select
        order0_.id as id1_0_0_,
        order0_.ordername as ordernam2_0_0_,
        order0_.userid as userid3_0_0_,
        user1_.id as id1_3_1_,
        user1_.name as name2_3_1_ 
    from
        t_order order0_ 
    left outer join
        user user1_ 
            on order0_.userid=user1_.id 
    where
        order0_.id=?
Hibernate: 
    update
        user 
    set
        name=? 
    where
        id=?

更新时不用persist再保存,提交事务时会自动将缓存保存到数据库,但是一定要提交事务。
很烦,不想写注释,反正自己看
参考文章
http://blog.csdn.net/je_ge/article/details/53493897

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