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Rain on your Parade
Time Limit: 3000MS |
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Memory Limit: 165535KB |
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64bit IO Format: %I64d & %I64u |
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Description
You’re giving a party in the garden of your villa by the sea. The party is a huge success, and everyone is here. It’s a warm, sunny evening, and a soothing wind sends fresh, salty air from the sea. The evening is progressing just as you had imagined. It could be the perfect end of a beautiful day.
But nothing ever is perfect. One of your guests works in weather forecasting. He suddenly yells, “I know that breeze! It means its going to rain heavily in just a few minutes!” Your guests all wear their best dresses and really would not like to get wet, hence they stand terrified when hearing the bad news.
You have prepared a few umbrellas which can protect a few of your guests. The umbrellas are small, and since your guests are all slightly snobbish, no guest will share an umbrella with other guests. The umbrellas are spread across your (gigantic) garden, just like your guests. To complicate matters even more, some of your guests can’t run as fast as the others.
Can you help your guests so that as many as possible find an umbrella before it starts to pour?
Given the positions and speeds of all your guests, the positions of the umbrellas, and the time until it starts to rain, find out how many of your guests can at most reach an umbrella. Two guests do not want to share an umbrella, however.
Output
For each test case, write a line containing “Scenario #i:”, where i is the number of the test case starting at 1. Then, write a single line that contains the number of guests that can at most reach an umbrella before it starts to rain. Terminate every test case with a blank line.
Sample Output
Scenario #1: 2 Scenario #2: 2
Source
题意:在一个二维坐标系上有n个人和m把伞,每个人都有自己的移动速度,问最多有多少人可以再t min内移动到不同的雨伞处(不允许两个人共用一把伞)。
思路:很明显是二分图的最大匹配问题,用普通DFS,BFS匈牙利算法妥当TLE,之后学了Hopcroft-Karp算法后回来再做;
有点奇怪的是用邻接矩阵无论是效率或空间都比邻接表或vector要好。。。
贴上邻接表代码:
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