[LeetCode162]Nim Game

题目来源：https://leetcode.com/problems/nim-game/   题目地址

You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.

Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.

For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.

题目分析：

有史以来最少代码量的解法，虽然解法很简单，但是题目还是蛮有意思的，题目说给我们一堆石子，每次可以拿一个两个或三个，两个人轮流拿，拿到最后一个石子的人获胜，现在给我们一堆石子的个数，问我们能不能赢。那么我们就从最开始分析，由于是我们先拿，那么3个以内(包括3个)的石子，我们直接赢，如果共4个，那么我们一定输，因为不管我们取几个，下一个人一次都能取完。如果共5个，我们赢，因为我们可以取一个，然后变成4个让别人取，根据上面的分析我们赢，所以我们列出1到10个的情况如下：

1    Win

2    Win

3    Win

4    Lost

5    Win

6    Win

7    Win

8    Lost

9    Win

10   Win

class Solution {
public:
    bool canWinNim(int n) {
        if(n % 4==0){
            return false;
        }
        else{
            return true;
            }
        
    }
};