HDU4421(2-sat)

拆位,每一位建一次图判断是否可行,如果一次性建完每一位的图然后跑一次2-sat会爆边。

#include <bits/stdc++.h>
using namespace std;
#define maxn 51111
#define maxm 5111111
#define index Index

int n;
long long b[511][511];
struct node {
    int to, next;
}edge[maxm];
int head[maxn], cnt;

int get_pos (int i) {
    return 2*(i);
}

void add_edge (int from, int to, int i) {
    node &e = edge[i];
    e.to = to, e.next = head[from], head[from] = i;
}

int low[maxn], dfn[maxn], s[maxn], belong[maxn];
int index, top, scc, num[maxn];
bool vis[maxn];

void tarjan (int u) {
    int v;
    low[u] = dfn[u] = ++index;
    s[++top] = u;
    vis[u] = 1;
    for (int i = head[u]; i != -1; i = edge[i].next) {
        v = edge[i].to;
        if (!dfn[v]) {
            tarjan (v);
            low[u] = min (low[u], low[v]);
        }
        else if (vis[v])
            low[u] = min (dfn[v], low[u]);
    }
    if (low[u] == dfn[u]) {
        scc++;
        do {
            v = s[top--];
            vis[v] = 0;
            belong[v] = scc;
        } while (v != u);
    }
}

bool two_sat () {
    memset (dfn, 0, sizeof dfn);
    memset (vis, 0, sizeof vis);
    memset (num, 0, sizeof num);
    index = scc = top = 0;
    for (int i = 0; i < n*2; i++) {
        if (!dfn[i])
            tarjan (i);
    }
    for (int i = 0; i < n*2; i += 2) {
        if (belong[i] == belong[i^1])
            return 0;
    }
    return 1;
}

void init () {
    memset (head, -1, sizeof head);
    cnt = 0;
}

int main () {
    //freopen ("in", "r", stdin);
    while (scanf ("%d", &n) == 1) {
        bool ok = 1;
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                scanf ("%lld", &b[i][j]);
            }
        }
        for (int bit = 0; bit < 31; bit++) {
            init ();
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < n; j++) {
                    if (i == j) {
                        if (b[i][j] == 0)
                            continue;
                        else {
                            ok = 0;
                            goto out;
                        }
                    }
                    int p = b[i][j]&(1<<bit);
                    int u = get_pos (i), v = get_pos (j);
                    if (i%2 == 0 && j%2 == 0) {
                        if (p) {
                            add_edge (u, u^1, cnt++);
                            add_edge (v, v^1, cnt++);
                        }
                        else {
                            add_edge (u^1, v, cnt++);
                            add_edge (v^1, u, cnt++);
                        }
                    }
                    else if ((i&1) && (j&1)) {
                        if (p) {
                            add_edge (u, v^1, cnt++);
                            add_edge (v, u^1, cnt++);
                        }
                        else {
                            add_edge (u^1, u, cnt++);
                            add_edge (v^1, v, cnt++);
                        }
                    }
                    else {
                        if (p) {
                            add_edge (u, v^1, cnt++);
                            add_edge (v, u^1, cnt++);
                            add_edge (u^1, v, cnt++);
                            add_edge (v^1, u, cnt++);
                        }
                        else {
                            add_edge (u^1, v^1, cnt++);
                            add_edge (v^1, u^1, cnt++);
                            add_edge (u, v, cnt++);
                            add_edge (v, u, cnt++);
                        }
                    }
                }
            }
            if (two_sat ()) {
                continue;
            }
            else {
                ok = 0;
                goto out;
            }
        }
        out: ;
        if (!ok) {
            printf ("NO\n");
        }
        else printf ("YES\n");
    }
    return 0;
}


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