压根没有想到用树状数组可以做。。。。一开始用KD树做,结果超时了。。。KD树查询的时候太慢了。。而且对于这道题目,貌似可以人工构造出一组数据把KD树卡成一条链。。。。。跪掉了。。
用树状数组就离线查询呗。。。把查询和点都按一维从小到大排好序,然后按另一维单点插入就好嘞。。。
#include <iostream> #include <sstream> #include <algorithm> #include <vector> #include <queue> #include <stack> #include <map> #include <set> #include <bitset> #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include <climits> #define maxn 200005 #define eps 1e-6 #define mod 10007 #define INF 99999999 #define lowbit(x) (x&(-x)) #define lson o<<1, L, mid #define rson o<<1 | 1, mid+1, R typedef long long LL; using namespace std; LL xx1, yy1, xx2, yy2; struct point { LL x, y; }po[maxn]; struct query { LL r1, r2; int res; int number; }q[maxn]; int tree[maxn]; LL yy[maxn]; int ycnt, n, m; int cmp1(LL a, LL b) { return a<b; } int cmp2(point a, point b) { return a.x>b.x; } int cmp3(query a, query b) { if(a.r1 == b.r1) return a.r2<b.r2; return a.r1>b.r1; } int cmp4(query a, query b) { return a.number<b.number; } void init(void) { memset(tree, 0, sizeof tree); } void add(int x) { for(int i = x; i > 0; i-=lowbit(i)) tree[i]++; } int sum(int x) { int ans = 0; for(int i = x; i <= ycnt; i+=lowbit(i)) ans += tree[i]; return ans; } void read(void) { int i; LL tmpx, tmpy; ycnt = 0; scanf("%d", &n); for(i = 1; i <= n; i++) { scanf("%lld%lld", &tmpx, &tmpy); po[i].x = (tmpx-xx1)*(tmpx-xx1) + (tmpy-yy1)*(tmpy-yy1); po[i].y = (tmpx-xx2)*(tmpx-xx2) + (tmpy-yy2)*(tmpy-yy2); yy[ycnt++] = po[i].y; } scanf("%d", &m); for(i = 1; i <= m; i++) { scanf("%lld%lld", &q[i].r1, &q[i].r2); q[i].number = i; q[i].r1*=q[i].r1; q[i].r2*=q[i].r2; yy[ycnt++] = q[i].r2; } } void work(void) { int i, j; sort(yy+1, yy+ycnt+1, cmp1); for(i = 2, j = 2; i <= ycnt; i++) if(yy[i] != yy[i-1]) yy[j++] = yy[i]; ycnt = j-1; sort(po+1, po+n+1, cmp2); sort(q+1, q+m+1, cmp3); } int search(LL tmp) { int bot = 1, top = ycnt, mid; while(top>=bot) { mid = (top+bot)>>1; if(yy[mid] == tmp) break; if(yy[mid] > tmp) top = mid-1; else bot = mid+1; } return mid; } void debug(void) { int i; printf("BBBB\n"); for(i = 1; i <= ycnt; i++) printf("%d\n", search(yy[i])); } void solve(void) { int i, j; for(i = 1, j = 1; i <= m; i++) { while(j <= n && po[j].x >= q[i].r1) add(search(po[j++].y)); q[i].res = sum(search(q[i].r2)); } sort(q+1, q+m+1, cmp4); for(i = 1; i <= m; i++) printf("%d\n", q[i].res); } int main(void) { while(scanf("%lld%lld%lld%lld", &xx1, &yy1, &xx2, &yy2)!=EOF) { init(); read(); work(); solve(); } return 0; }