搜索简单题——Knight Moves

#include<iostream>
#include<queue>
#include<stdio.h>
using namespace std;
struct node
{
    int x;
    int y;
    int step;
};
int a[]={-2,-1,1,2,2,1,-1,-2};
int b[]={1,2,2,1,-1,-2,-2,-1};
int countStep(node start,node end)
{
    node tmp;
    node frt;
    if(start.x==end.x&&start.y==end.y)
    return 0;
    queue<node> q;
    q.push(start);
    while(!q.empty())
    {
        frt=q.front();
        q.pop();
        for(int i=0;i<8;i++)
        {
            tmp.x=a[i]+frt.x;
            tmp.y=b[i]+frt.y;
            tmp.step=frt.step+1;
            if(tmp.x==end.x&&tmp.y==end.y)
            return tmp.step;
            if(tmp.x>=1&&tmp.x<=8&&tmp.y>=1&&tmp.y<=8)
            q.push(tmp);
        }
    }
}
int main()
{
    int a,b;
    char c1,c2;
    node start,end;
    while(scanf("%c%d %c%d",&c1,&a,&c2,&b)!=EOF)
    {
        start.step=0;
        start.x=c1-'a'+1;
        start.y=a;
        end.x=c2-'a'+1;
        end.y=b;
        printf("To get from %c%d to %c%d takes %d knight moves.\n",c1,a,c2,b,countStep(start,end));
        getchar();
    }
    return 0;
}

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