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ACM_比赛题解
[
ACM_
动态规划] UVA 12511 Virus [最长公共递增子序列 LCIS 动态规划]
Virus We have a log file, which is a sequence of recorded events. Naturally, the timestamps are strictly increasing. However, it is infected by a virus, so random
·
2015-10-31 11:36
动态规划
[
ACM_
动态规划] hdu 1176 免费馅饼 [变形数塔问题]
Problem Description 都说天上不会掉馅饼,但有一天gameboy正走在回家的小径上,忽然天上掉下大把大把的馅饼。说来gameboy的人品实在是太好了,这馅饼别处都不掉,就掉落在他身旁的10米范围内。馅饼如果掉在了地上当然就不能吃了,所以gameboy马上卸下身上的背包去接。但由于小径两侧都不能站人,所以他只能在小径上接。由于gameboy平时老
·
2015-10-31 11:36
动态规划
[
ACM_
模拟] ACM - Draw Something Cheat [n个长12的大写字母串,找出交集,按字母序输出]
Description Have you played Draw Something? It's currently one of the hottest social drawing games on Apple iOS and Android Devices! In this game, you and your friend play in turn. You
·
2015-10-31 11:36
ACM
[
ACM_
数学] LA 3708 Graveyard [墓地雕塑 圈上新加点 找规律]
Description Programming contests became so popular in the year 2397 that the governor of New Earck -- the largest human-inhabited planet of the galaxy -- opened a special Alley of
·
2015-10-31 11:36
ACM
[
ACM_
水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for g
·
2015-10-31 11:36
water
[
ACM_
模拟][
ACM_
数学] LA 2995 Image Is Everything [由6个视图计算立方体最大体积]
Description Your new company is building a robot that can hold small lightweight objects. The robot will have the intelligence to determine if an object is light enough to hold. It
·
2015-10-31 11:36
image
[
ACM_
图论] The Perfect Stall 完美的牛栏(匈牙利算法、最大二分匹配)
描述 农夫约翰上个星期刚刚建好了他的新牛棚,他使用了最新的挤奶技术。不幸的是,由于工程问题,每个牛栏都不一样。第一个星期,农夫约翰随便地让奶牛们进入牛栏,但是问题很快地显露出来:每头奶牛都只愿意在她们喜欢的那些牛栏中产奶。上个星期,农夫约翰刚刚收集到了奶牛们的爱好的信息(每头奶牛喜欢在哪些牛栏产奶)。一个牛栏只能容纳一头奶牛,当然,一头奶牛只能在一个牛栏中产奶。 给出奶牛们的爱好的信息,计算最
·
2015-10-31 11:35
ACM
[
ACM_
搜索] ZOJ 1103 || POJ 2415 Hike on a Graph (带条件移动3盘子到同一位置的最少步数 广搜)
Description "Hike on a Graph" is a game that is played on a board on which an undirected graph is drawn. The graph is complete and has all loops, i.e. for any two locations there is exactly
·
2015-10-31 11:35
Graph
[
ACM_
图论] Fire Net (ZOJ 1002 带障碍棋盘布炮,互不攻击最大数量)
Suppose that we have a square city with straight streets. A map of a city is a square board with n rows and n columns, each representing a street or a piece of wall. A blockhouse is a small cas
·
2015-10-31 11:35
ACM
[
ACM_
图论] Sorting Slides(挑选幻灯片,二分匹配,中等)
Description Professor Clumsey is going to give an important talk this afternoon. Unfortunately, he is not a very tidy person and has put all his transparencies on one big heap. Before giving the talk
·
2015-10-31 11:35
sort
[
ACM_
搜索] Triangles(POJ1471,简单搜索,注意细节)
Description It is always very nice to have little brothers or sisters. You can tease them, lock them in the bathroom or put red hot chili in their sandwiches. But there is also a time when all meanne
·
2015-10-31 11:35
ACM
[
ACM_
动态规划] ZOJ 1425 Crossed Matchings(交叉最大匹配 动态规划)
Description There are two rows of positive integer numbers. We can draw one line segment between any two equal numbers, with values r, if one of them is located in the first row and the other one is
·
2015-10-31 11:35
match
[
ACM_
搜索] POJ 1096 Space Station Shielding (搜索 + 洪泛算法Flood_Fill)
Description Roger Wilco is in charge of the design of a low orbiting space station for the planet Mars. To simplify construction, the station is made up of a series of Airtight Cubical Modules (ACM's
·
2015-10-31 11:35
ACM
[
ACM_
几何] Transmitters (zoj 1041 ,可旋转半圆内的最多点)
Description In a wireless network with multiple transmitters sending on the same frequencies, it is often a requirement that signals don't overlap, or at least that they don't conflict. One way of a
·
2015-10-31 11:35
ACM
[
ACM_
模拟] The Willy Memorial Program (poj 1073 ,联通水管注水模拟)
Description Willy the spider used to live in the chemistry laboratory of Dr. Petro. He used to wander about the lab pipes and sometimes inside empty ones. One night while he was in a pipe, he fell as
·
2015-10-31 11:35
ACM
[
ACM_
其他] Square Ice (poj1099 规律)
Description Square Ice is a two-dimensional arrangement of water molecules H2O, with oxygen at the vertices of a square lattice and one hydrogen atom between each pair of adjacent oxygen atoms. The
·
2015-10-31 11:35
ACM
[
ACM_
图论] Highways (变形说法的最小生成树)
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28972#problem/C 题目给出T种情况,每种情况有n个城镇,接下来每一行是第i个城镇到所有城镇的距离(其实就是个可达矩阵)。 求建设一条公路联通所有城镇并且要求最长的一段最小(其实就是最小生成树)!代码如下: #include<
·
2015-10-31 11:34
最小生成树
[
ACM_
数学] Counting Solutions to an Integral Equation (x+2y+2z=n 组合种类)
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=27938#problem/E 题目大意:Given, n, count the number of solutions to the equation x+2y+2z=n, where x,y,z,n are non negative inte
·
2015-10-31 11:34
count
[
ACM_
几何] The Deadly Olympic Returns!!! (空间相对运动之最短距离)
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28235#problem/B 题目大意: 有两个同时再空间中匀速运动的导弹,告诉一个时间以及各自的初始坐标和该时间时的坐标,求运动过程中的最短距离 解题思路: 求出相对初位置、相对速度,则答案就是原点到射线型轨迹的距离,注意是射线!!!
·
2015-10-31 11:34
return
[
ACM_
几何] F. 3D Triangles (三维三角行相交)
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28235#problem/A 题目大意:给出三维空间两个三角形三个顶点,判断二者是否有公共点,三角形顶点、边、内部算三角形的一部分。 解题思路:见模板 //**********************************************
·
2015-10-31 11:34
ACM
[
ACM_
动态规划] 轮廓线动态规划——铺放骨牌(状态压缩1)
Description Squares and rectangles fascinated the famous Dutch painter Piet Mondriaan. One night, after producing the drawings in his 'toilet series' (where he had to use his toilet paper to draw on
·
2015-10-31 11:34
动态规划
[
ACM_
图论] 棋盘问题 (棋盘上放棋子的方案数)
不能同行同列,给定形状和大小的棋盘,求摆放k个棋子的可行方案 Input 2表示是2X2的棋盘,1表示k,#表示可放,点不可放(-1 -1 结束) Output 输出摆放的方案数目C Sample Input 2 1 #. .# 4 4 ...# ..#. .#.. #... -1 -1 Sample Output 2 1
·
2015-10-31 11:34
ACM
[
ACM_
其他] 总和不小于S的连续子序列的长度的最小值——尺缩法
Description: 给定长度为n的整数数列,A[0],A[1],A[2]….A[n-1]以及整数S,求出总和不小于S的连续子序列的长度的最小值。如果解不存在,则输出0。 Input: 输入数据有多组,每组数据第一行输入n,S, (10<n<10^5,S<10^8)第二行输入A[0],A[1],A[2]….A[n-1] ( 0<A[i]≤10000)
·
2015-10-31 11:34
ACM
[
ACM_
几何] Metal Cutting(POJ1514)半平面割与全排暴力切割方案
Description In order to build a ship to travel to Eindhoven, The Netherlands, various sheet metal parts have to be cut from rectangular pieces of sheet metal. Each part is a convex polygon with at mo
·
2015-10-31 11:34
meta
[
ACM_
动态规划] Palindrome
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28415#problem/D 题目大意:给一个长为n的字符串,问最少插入几个字符成回文串 解题思路:总长-最长公共(原来的和其倒过来的串)子序列(LCS) 知识详解——LCS:给出两个子序列A,B,求长度最大的公共子序列(如152687和2356984——
·
2015-10-31 11:33
动态规划
[
ACM_
动态规划] Alignment (将军排队)
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28415#problem/F 题目大意:有n个士兵排成一列,将军想从中抽出最少人数使队伍中任何士兵都能够看到左边最远处或右边最远处 解题思路:①此题是最长上升子序列的升级版。 &
·
2015-10-31 11:33
动态规划
[
ACM_
贪心] Radar Installation
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28415#problem/A 题目大意:X轴为海岸线可放雷达监测目标点,告诉n个目标点和雷达监测半径,求最少多少个雷达可全覆盖,如果不能输出-1; 解题思路:赤裸裸的区间选点问题(数轴上有n个闭区间,去尽量少的点,使每个区间至少有一个点)。核心思想就是贪心算法:把所有区间按照b从小
·
2015-10-31 11:33
Install
[
ACM_
几何] Pipe
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28417#problem/B 本题大意: 给定一个管道上边界的拐点,管道宽为1,求一束光最远能照到的地方的X坐标,如果能照到终点,则输出...  
·
2015-10-31 11:33
ACM
[
ACM_
几何] Wall
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28417#problem/E 题目大意:依次给n个点围成的一个城堡,在周围建围墙,要求围墙离城墙的距离大于一定的值,求围墙最短长度(结果四舍五入 解题思路:求围住所有点的凸包周长+一个圆的周长 #include<iostream> #include<cma
·
2015-10-31 11:33
ACM
[
ACM_
动态规划] 找零种类
问题描述:假设某国的硬币的面值有 1、5、10、50 元四种,输入一个金额 N (正整数,N<=1000),印出符合该金额的硬币组合有多少种。 问题分析: 1、5、10 元组合出 N 元的方法数 = 以 1、5 元组合出 N 元的方法数 + 以 1、5、10 元组合出 N - 10 元的方法数(其他类推) #include<iostream> #in
·
2015-10-30 18:08
动态规划
[
ACM_
几何] Fishnet
http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28417#problem/C 本题大意:有一个1X1的矩形,每边按照从小到大的顺序给n个点如图,然后对应连线将举行划分,求最大面积。 解题思路:暴力算出各点,求出各面积 #include<iostream> #incl
·
2015-10-30 18:08
ACM
[
ACM_
动态规划] 嵌套矩形
问题描述: 有n个矩阵,每个矩阵可以用两个整数a,b来表示 ,表示他的长和宽,矩阵X (a,b) 可以 嵌套 到Y (c,d) 里面当且仅当 a < c && b < d || a < d && b < c . 选出最多这种矩阵。先输出最多的数量,在输出最小字典序路径。 问题分析:本题是DAG(有向无
·
2015-10-30 18:08
动态规划
[
ACM_
动态规划] 最长上升子序列(LIS)
问题描述:给n个数,找出最长子序列并输出 问题分析: 本题是DAG(有向无环图)最长路问题,设d[i]为以i结尾的最长链的长度,则状态转移方程为:d[i]=max{0,d[j]|j<i && A[j]<A[i]}+1 ; solve one: 这里用map[i][j]存储第i个和第j个的关系0-1邻接矩阵;套用标准解DAG的模板,利用dfs求解
·
2015-10-30 18:08
动态规划
[
ACM_
动态规划] 数字三角形(数塔)
递归方法解决数塔问题 状态转移方程: d[i][j]=a[i][j]+max{d[i+1][j],d[i+1][j+1]} 注意:1\d[i][j]表示从i,j出发的最大总和; 2\变界值设为0;3\递归变界为n; 4\结果为d[1][1] #include<iostream> #include<algorithm> using namespace
·
2015-10-30 18:07
动态规划
[
ACM_
动态规划] 数字三角形(数塔)_递推_记忆化搜索
1、直接用递归函数计算状态转移方程,效率十分低下,可以考虑用递推方法,其实就是 “正着推导,逆着计算” #include<iostream> #include<algorithm> using namespace std; #define maxn 1000+5 int n; int a[maxn][maxn]; int d[maxn][maxn];
·
2015-10-30 18:07
动态规划
卡特兰数 Catalan数 ( ACM 数论 组合 )
组合 ) Posted on 2010-08-07 21:51 MiYu 阅读(13170) 评论(1) 编辑 收藏 引用 所属分类: ACM ( 数论 ) 、
ACM
·
2015-10-28 08:51
ACM
[
ACM_
数据结构] Color the ball [线段树水题][数组开大]
Description N个气球排成一排,从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气球a开始到气球b依次给每个气球涂一次颜色。但是N次以后lele已经忘记了第I个气球已经涂过几次颜色了,你能帮他算出每个气球被涂过几次颜色吗? Input 每个测试实例
·
2015-10-27 14:03
color
[
ACM_
数据结构] 线段树模板
#include<iostream> #include<cmath> using namespace std; #define maxn 200005 class Node{ public: int l,r; int add;//附加值 int sum; }node[maxn]; int getRight(int
·
2015-10-27 14:03
数据结构
[
ACM_
数据结构] HDU 1166 敌兵布阵 线段树 或 树状数组
1 #include<iostream> 2 #include<cstdio> 3 #include<memory.h> 4 using namespace std; 5 int n,C[50005]; 6 //-------------------------- 7 int lowbit(int x){ 8
·
2015-10-27 14:03
数据结构
[
ACM_
暴力] 最多交换k个数的顺序,求a[i]的最大连续和
1 /* 2 http://codeforces.com/contest/426/problem/C 3 最多交换k个数的顺序,求a[i]的最大连续和 4 爆解 5 思路:Lets backtrack interval that should contain maximal sum. 6 To improve it we can swap
·
2015-10-27 14:02
ACM
[
ACM_
模拟] HDU 1006 Tick and Tick [时钟间隔角度问题]
Problem Description The three hands of the clock are rotating every second and meeting each other many times everyday. Finally, they get bored of this and each of them would like to
·
2015-10-27 14:02
ACM
[
ACM_
模拟] UVA 10881 Piotr's Ants[蚂蚁移动 数组映射 排序技巧]
"One thing is for certain: there is no stopping them;the ants will soon be here. And I, for one, welcome ournew insect overlords." Kent Brockman Piotr likes
·
2015-10-27 14:01
ant
[
ACM_
动态规划] hdu1003 Max Sum [最大连续子串和]
Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (
·
2015-10-27 14:01
动态规划
[
ACM_
其他] Modular Inverse [a关于模m的逆 模线性方程]
Description The modular modular multiplicative inverse of an integer a modulo m is an integer x such that a-1≡x (mod m). This is equivalent toax
·
2015-10-27 14:59
inverse
[
ACM_
水题] Yet Another Story of Rock-paper-scissors [超水 剪刀石头布]
Description Akihisa and Hideyoshi were lovers. They were sentenced to death by the FFF Inquisition. Ryou, the leader of the FFF Inquisition, promised that the winner of Rock-paper-scissors
·
2015-10-27 14:59
ACM
[
ACM_
数学] Taxi Fare [新旧出租车费差 水 分段函数]
Description Last September, Hangzhou raised the taxi fares. The original flag-down fare in Hangzhou was 10 yuan, plusing 2 yuan per kilometer after the first 3km and 3 yuan per kilometer after 10km
·
2015-10-27 14:59
ACM
[
ACM_
模拟][
ACM_
暴力] Lazier Salesgirl [暴力 懒销售睡觉]
Description Kochiya Sanae is a lazy girl who makes and sells bread. She is an expert at bread making and selling. She can sell the i-th customer a piece of bread for price pi. But
·
2015-10-27 14:59
ACM
[
ACM_
几何] UVA 11300 Spreading the Wealth [分金币 左右给 最终相等 方程组 中位数]
Problem A Communist regime is trying to redistribute wealth in a village. They have have decided to sit everyone around a circular table. First, everyone has converted all of their properties
·
2015-10-27 14:57
reading
[
ACM_
水题] UVA 11729 Commando War [不可同时交代任务 可同时执行 最短完成全部时间 贪心]
There is a war and it doesn't look very promising for your country. Now it's time to act. You have a commando squad at your disposal and planning an ambush on an important enemy camp located n
·
2015-10-27 14:57
command
[
ACM_
模拟] ZOJ 3713 [In 7-bit 特殊输出规则 7bits 16进制]
Very often, especially in programming contests, we treat a sequence of non-whitespace characters as a string. But sometimes, a string may contain whitespace characters or even be empty
·
2015-10-27 14:56
ACM
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