hdu1086

hdu1086 You can Solve a Geometry Problem too （判断两线段是否相交）

YoucanSolveaGeometryProblemtooTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):9195AcceptedSubmission(s):4498ProblemDescriptionManygeometry（几何）problemsweredesi
yuyanggo·2020-08-23 00:08

HDU1086：You can Solve a Geometry Problem too(线段相交模板)

ProblemDescriptionManygeometry（几何）problemsweredesignedintheACM/ICPC.Andnow,Ialsoprepareageometryproblemforthisfinalexam.AccordingtotheexperienceofmanyACMers,geometryproblemsarealwaysmuchtrouble,butthi
键盘上的舞者·2020-08-22 22:24

hdu1086 You can Solve a Geometry Problem too 计算几何求线段交点个数，快速排斥实验+跨立实验

YoucanSolveaGeometryProblemtooTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):8229AcceptedSubmission(s):4007ProblemDescriptionManygeometry（几何）problemsweredesi
Lionel_D·2020-08-22 21:11

HDU1086 You can Solve a Geometry Problem too

YoucanSolveaGeometryProblemtooTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):10594AcceptedSubmission(s):5246ProblemDescriptionManygeometry（几何）problemsweredes
BorntoDo·2020-08-22 20:03

hdu1086 You can Solve a Geometry Problem too（判断线段相交）

hdu1086YoucanSolveaGeometryProblemtoo（判断线段相交）题目描述Manygeometry（几何）problemsweredesignedintheACM/ICPC.Andnow,Ialsoprepareageometryproblemforthisfinalexam.AccordingtotheexperienceofmanyACMers,geometryprob
SADON_jung·2020-06-22 07:02

hdu1086 You can Solve a Geometry Problem too

YoucanSolveaGeometryProblemtooTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):9306    AcceptedSubmission(s):4563ProblemDescriptionManygeometry（几何）problems
EventQueue·2016-01-27 15:00

hdu1086(线段相交)

题目意思： 给出n个线段，推断这n条线段中，线段相交的对数。 http://acm.hdu.edu.cn/showproblem.php?pid=1086 题目分析： 此题主要写出推断线段相交的函数，然后推断每一对线段就可以，时间复杂度O(n*n)。详解见代码。 AC代码： /**  *推断AB和CD两线段是否有交点：  *同一时候满足两个条件：('x
·2015-11-13 17:06

HDU1086

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8452    Accepted S
·2015-11-09 13:12

HDU 1147 poj 2653 Pick-up sticks

该题与HDU1086相似都是线段相交的问题，在这里就不解释线段相交了（ 在HDU 1086 You can Solve a Geometry Problem too已经解释了）不过我的代码还是注释一下
·2015-11-02 18:09

判断两条线段是否相交

模板(hdu1086)   include <iostream> using namespace std; struct point { double
·2015-11-02 13:50

You can Solve a Geometry Problem too （hdu1086）几何，判断两线段相交

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6837 Accepted Submission(s): 3303 Problem Description
·2015-10-31 09:33

Training：计算几何基础

HDU1086：http://acm.hust.edu.cn/vjudge/problem/visitOriginUrl.action?id=17612给出n条线段，求其中相交的对数。
wcr1996·2015-06-10 23:00

HDU 1086 You can Solve a Geometry Problem too(判断线段相交）

题目地址：HDU1086就这么一道仅仅判断线段相交的题目写了2k多B的代码。。是不是有点浪费。。。但是我觉得似乎哪里也优化不了了。。。。判断线段相交就是利用的叉积。
u013013910·2014-08-13 21:00

HDU1086 You can Solve a Geometry Problem too

PS:主要解决线段相交中规范相交和不规范相交。#include #include #include #include #include #include usingnamespacestd; constdoubleeps=1e-8; intdcmp(doublex){ if(fabs(x)0?1:-1; } structpoint{ doublex,y; point(doublex=0,doub
wangwenhao00·2014-04-26 13:00

ACM-计算几何之You can Solve a Geometry Problem too——hdu1086

YoucanSolveaGeometryProblemtoo题目：http://acm.hdu.edu.cn/showproblem.php?pid=1086ProblemDescriptionManygeometry（几何）problemsweredesignedintheACM/ICPC.Andnow,Ialsoprepareageometryproblemforthisfinalexam.A
lx417147512·2014-04-21 14:00

判断两条线段是否相交

模板(hdu1086)include usingnamespacestd; structpoint { doublex,y; }; structsegment { pointbegin
GeiZuoZuoZuo·2013-08-18 13:00

我的计算几何学题目分类

UVa11646SDUTOJ2603poj1269poj1410poj1328（贪心）UVa12304（三角、圆基本关系）poj1556（线段相交+最短路）poj2966（凸包+最短路）poj2031（最小生成树）点积叉积poj2318poj2398（二分）hdu1086
zhengnanlee·2013-07-24 22:00

HDU1086

http://acm.hdu.edu.cn/showproblem.php?pid=1086判断是否相交，可看一条线段的两个端点是否在另一条直线的两侧，如下图：在数学中，向量的点乘，大小等于其模的成绩再乘以家教的正弦值，方向符合右旋法则（右手系），意义是其表示的平行四边形的面积。如果两个点在一条线的同一侧，如图，那么他们的点乘积应大于0，或程序中的大于eps（精度Epsilon）另外注意线段相交的
zhengnanlee·2013-07-16 14:00

hdu1086 You can Solve a Geometry Problem too

#include //(abXac)(abXad)<0&&(cdXca)(cdXcb)<0 structsegment { doublex1,y1,x2,y2; }seg[102]; intJudge(inti,intj) { doublea,b,c,d,x,y,a1,b1; a=seg[i].x1-seg[j].x1; b=seg[i].y1-seg[j].y1; a1=seg[i].x2-s
lezong2011·2013-07-11 18:00

HDU1086：You can Solve a Geometry Problem too(线段相交模板)

ProblemDescriptionManygeometry（几何）problemsweredesignedintheACM/ICPC.Andnow,Ialsoprepareageometryproblemforthisfinalexam.AccordingtotheexperienceofmanyACMers,geometryproblemsarealwaysmuchtrouble,butthi
libin56842·2013-06-09 18:00

hdu1086

/*分析：  15MS，和我估计的一样--III，因为对于斜率的计算，同一个斜率重复计算了好多次，可以只算一次，然后用个表存下来，用的时候直接用就行了。优化下下。judge函数解释见下。方法看起来挺麻烦的--III，谁有判断两线段是否相交的更好的方法，欢迎分享哈。                               2012-04-12*/#include"stdio.h" intjudg
Ice_Crazy·2012-04-12 11:00

计算几何题目分类+简单解释

poj1259最大内部凸包hdu3644多边形内能放进最大圆半径（可能是凹的，二分+判断）//hdu1086 //hdu3982半平面交+求凸多边形和圆的面积交//hdu4063注意判断线段是否被圆覆盖的
zxy_snow·2011-11-09 13:00

hdu 1086 计算几何入门题

hdu1086计算几何入门题这是hdu上面的入门几何题 判断线段相交，在算法导论上有相应的算法而且这道题没有考虑多条线段相交一点的情况http://acm.hdu.edu.cn/showproblem.php
付翔的专栏·2010-04-17 11:00
上一页 1 下一页
按字母分类： ABCDEFGHIJKLMNOPQRSTUVWXYZ其他