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polynomial
Codeforces 493E Vasya and
Polynomial
(数学)
题目链接:Codeforces493EVasyaandPolynomial#include #include #include usingnamespacestd; typedeflonglongll; llt,a,b; intmain(){ scanf("%lld%lld%lld",&t,&a,&b); if(t==a){ if(a==b) printf("%s\n",t==1?"inf"
u011328934
·
2015-04-12 19:00
Nomial
Somehow,Iusednottounderstandthesuffixnomialinwordse.g.multinomial,binomial,
polynomial
.Itseems,mostofthetime
visionfans
·
2015-04-04 22:00
02-线性结构1. 一元多项式求导 链表
#include #include usingnamespacestd; typedefstructpolynode*
polynomial
; structpolynode { intcoef; intexpon
xinag578
·
2015-03-28 09:00
UVA - 10105
Polynomial
Coefficients
题目大意:给出n和m,再该出m个数值n1~nm,保证n1+...+nm=n,现在有算式(a1+a2+...+am)^n,求展开项中a1^n1+a2^n2+...+am^nm这项的系数。解题思路:(a+b)^n的系数为C(i,n),那么对于算式(a1+a2+...+am)^n可以理解成(X+am)^n,类似于递归的操作。#include intmain(){ intn,k,C[20][20]={0
kl28978113
·
2015-03-17 23:00
Polynomial
Curve Fitting
PolynomialCurveFittingEtharaPolynomialcurvefittingproblemissuchthat,inatwodimensionalplane,givenasetofmsamplepoints,Figure1youareaskedtofitthemintoann-orderpolynomialcurveinananalyticalform,Howarewesu
Ethara
·
2014-12-23 18:00
Polynomial
Library in OpenCascade
[email protected]
摘要Abstract:分析幂基曲线即多项式曲线在OpenCascade中的计算方法,以及利用OpenSceneGraph来显示OpenCascade的计算结果,加深对多项式曲线的理解。 关键字KeyWords:OpenCascade、PLib、OpenSceneGraph、PolynomialLibrary
eryar
·
2014-11-23 12:00
UVA10105 -
Polynomial
Coefficients(排列组合)
UVA10105-PolynomialCoefficients(排列组合)题目链接题目大意:给你k个数,然后求(x1+x2+x3+..+xk)^n的x1^n1x2^n2x3^n3...xk^nk这个数的系数。题目会给n和k,然后给出k个ni,并且保证n1+n2+..+nk=n.解题思路:根据二项式的系数的求法,类似的也用组合来求这个数的系数。对于这个x1^n1..xk^nk这个数的系数,就等于每个
u012997373
·
2014-11-14 15:00
UVa 498 - Polly the
Polynomial
题目:一直多项式的系数,求不同的x对应多项式的值。分析:数学题,简单题。直接代入多项式计算即可。说明:注意输入格式。#include #include #include #include usingnamespacestd; inttemp,c[10000]; intmain() { intn; while((temp=getchar())!=EOF){ intcount=0; while(
mobius_strip
·
2014-10-29 17:00
最大流算法统计
对最大流算法历史文献的一个调研 Table:
Polynomial
algorithms for the max flow problem No
·
2014-10-29 15:00
最大流
实现多项式的JAVA类
nbsp; package practice; 2 // http://introcs.cs.princeton.edu/java/92symbolic/
Polynomial
.java.html
·
2014-09-30 02:00
java
acdream(18) Integration of
Polynomial
题目链接:点击打开链接简单定积分,注意求gcd时要保证两个数都非负不然会出问题。。代码:#include #include #include usingnamespacestd; intgcd(inta,intb){ returnb?gcd(b,a%b):a; } inta[1010]; inte[1010]; intc[1010]; voidsolve(intn){ for(inti=1;
Baoli1008
·
2014-09-09 19:00
定积分
P NP 问题
多项式,
polynomial
。具体概念见《数学基础》,http://blog.csdn.net/chuchus/article/details/39136943 。
chuchus
·
2014-09-08 16:00
数学基础
多项式,
polynomial
。由若干个单项式的和组成的代数式叫做多项式,这些单项式中的最高次数,就是这个多项式的次数。如ax*x+bx+c。
chuchus
·
2014-09-08 15:00
UVA - 10951
Polynomial
GCD (最大公共多项式)
DescriptionProblemCPolynomialGCDInput:standardinputOutput:standardoutputGiventwopolynomialsf(x)andg(x)inZn,youhavetofindtheirGCDpolynomial,ie,apolynomialr(x)(alsoinZn)whichhasthegreatestdegreeofallthe
u011345136
·
2014-08-25 15:00
【DataStructure】Another usage of List:
Polynomial
Statements:Thisblogwaswrittenbyme,butmostofcontent isquotedfrombook【DataStructurewithJavaHubbard】 【Description】Apolynomialis a mathematical function of the form:p(x) = a0xn+ a1xn–1+a2xn–2+ ˜˜˜+an–1
sxb0841901116
·
2014-08-11 20:00
java
Collection
DataStructure
UVA 10105
Polynomial
Coefficients
组合数打表。(x1+x2+...+xk)^n中的任意一项为C(n,n1)*x1^n1*C(n-n1,n2)*x^n2*C(n-n1-n2,n3)*x^n3*......#include #include #include typedeflonglongll; usingnamespacestd; llc[15][15]; voidmake_table() { memset(c,0,sizeofc
u011281853
·
2014-07-30 22:00
D - Factoring a
Polynomial
D- FactoringaPolynomialTimeLimit:2000MS MemoryLimit:65536KB 64bitIOFormat:%I64d&%I64uSubmit StatusDescriptionRecentlyGeorgiehaslearnedaboutpolynomials.Apolynomialinonevariablecanbeviewedasafor
u014028231
·
2014-07-25 11:00
一元多项式的基本操作
defineNUM4 usingnamespacestd; classPolynomial{ public: //输入m项的系数和指数,建立表示一元多项式的有序链表P voidCreatePolyn(
polynomial
u014033518
·
2014-07-24 19:00
链表
指针
一元多项式
函数间调用
Uva 10719 - Quotient
Polynomial
(多项式求解)
ProblemBQuotientPolynomialTimeLimit2SecondsApolynomialofdegree n canbeexpressedasIf k isanyintegerthenwecanwrite:Here q(x) iscalledthequotientpolynomialof p(x) ofdegree (n-1) and r isanyintegerwhichis
HelloWorld10086
·
2014-07-24 14:00
uva
Polynomial
Quotient
POJ 2126 Factoring a
Polynomial
FactoringaPolynomialTimeLimit: 2000MS MemoryLimit: 65536KTotalSubmissions: 2412 Accepted: 1256DescriptionRecentlyGeorgiehaslearnedaboutpolynomials.Apolynomialinonevariablecanbeviewedasaformalsumanxn +
u013263923
·
2014-07-23 14:00
UVA 10719 (暑假-数学(3) - C - Quotient
Polynomial
)
#include constintMAX=10050; intmain(){ intk; while(scanf("%d",&k)!=EOF){ intarr[MAX],brr[MAX]; inti=0; charc; while(scanf("%d%c",&arr[i],&c)&&c!='\n'){ if(i!=0) brr[i]=arr[i]+k*brr[i-1]; else brr[i]=
kl28978113
·
2014-07-21 17:00
UVA 10719 Quotient
Polynomial
简单题
题目给出多项式P(x)=anx^n+an-1x^(n-1)+...+a0中的所有系数ai,按顺序给出,给定整数k,求使得P(x)=(x-k)q(x)+r中q(x)=bn-1x^(n-1)+bn-2x^(n-2)+...+b0中的bi和最后的r显然有关系式an=bn-1 an-1= bn-2-k*bn-1..... 既有ai=bi-1-k*bi其中bn=0; r-k*b0=a0故只要处理好输入的ai
u013738743
·
2014-07-09 19:00
简单题
Polynomial
Quotient
UVA10179
uva 10951 -
Polynomial
GCD(欧几里得)
题目链接:uva10951-PolynomialGCD题目大意:给出n和两个多项式,求两个多项式在所有操作均模n的情况下最大公约数是多少。解题思路:欧几里得算法,就是为多项式这个数据类型重载取模运算符,需要注意的是在多项式除多项的过程中,为了保证各项系数为整数,需要将整个多项式的系数整体扩大至一定倍数,碰到先除后模的时候要用逆元。#include #include constintmaxn=10
u011328934
·
2014-07-03 19:00
10105
Polynomial
Coefficients 组合数打表
#include #include #include usingnamespacestd; #defineN13 #defineMAXD100+10 intC[N][N]; voidGet_C(){ memset(C,0,sizeof(C)); for(inti=0;i0){ t=t-array[i-1]; ans=ans*C[t][array[i]]; } elseif(i==0){ ans=a
u013451221
·
2014-05-31 12:00
uva 10586 -
Polynomial
Remains(数论)
题目链接:uva10586-PolynomialRemains题目大意:给出一个n和k,表示有一个一元n次方程,有0次幂开始给出系数,用这个式子去除以x^k+1,求剩下的一元n-k次方程。解题思路:模拟除的过程即可,注意k #include #include usingnamespacestd; constintN=10005; intn,k,a[N]; intmain(){ while(s
u011328934
·
2014-04-13 15:00
斐波那契数列(Fibonacci
polynomial
)----动态规划
我以前发过一道题是用递归求解,但是递归的时间复杂度偏高所以就研究用动态规划求解,此代码每次都会保留运算的结果以便于下次调用代码如下:#includeusingnamespacestd;constintN(10);longfibo(intn);intmain(){ longf=fibo(N); cout<
u012965373
·
2014-04-09 21:00
Simulated Annealing Minimization: Single variable
polynomial
C++ source code.
Findingtheminimumofx^2-9x+20throughsimulatedannealing:Thisisaverysimpleexampleproblem.Mostpeoplethatareinterestedinsimulatedannealingprobablycouldfigureouttheanswerwithoutevenapenandpaper,sothisisjust
lcj_cjfykx
·
2014-03-12 03:00
表达式求解
include usingnamespacestd; structunit { floatcoef;//系数 intexpn;//指数 }; typedefstructpolynomial { unite;
polynomial
fobdddf
·
2014-02-19 10:00
10719 - Quotient
Polynomial
题目:10719-QuotientPolynomial题目大意:就是给一个多项式,和k,求除以(x-k)的商和余数。解题思路:多项式的系数si,商的系数xi,则有这样的关系:x1=s1;xi=si+k*x(i-1),(1 constintN=10005; ints[N],k,count; charch; intmain(){ while(scanf("%d%*c",&k)!=EOF){ co
u012997373
·
2014-01-19 18:00
UVa:10105
Polynomial
Coefficients(多项式定理)
多项式定理的应用,纯水题。 #include #include #include #include #include #defineMAXN1005 #defineINF2139062143 #definelllonglong usingnamespacestd; llFac(intval) { llres=1; for(inti=1;i<=val;++i) res*=i
kkkwjx
·
2014-01-11 15:00
数学
多项式定理
2013秋13级预备队集训练习4 --F - Quotient
Polynomial
ProblemBQuotientPolynomialTimeLimit2SecondsApolynomialofdegreencanbeexpressedasIfkisanyintegerthenwecanwrite:Hereq(x)iscalledthequotientpolynomialofp(x)ofdegree(n-1)andrisanyintegerwhichiscalledtherem
u013015642
·
2014-01-02 20:00
Quotient
Polynomial
第一次的时候理解错题意了,以为是输入与K有关。。。我也不知道我怎么想的。。。反正后来改对啦ProblemBQuotientPolynomialTimeLimit2SecondsApolynomialofdegree n canbeexpressedasIf k isanyintegerthenwecanwrite:Here q(x) iscalledthequotientpolynomialof
u013013910
·
2013-12-29 20:00
编程
C语言
UVA 10105
Polynomial
Coefficients(数论)
Polynomialcoefficients TheProblemTheproblemistocalculatethecoefficientsinexpansionofpolynomial (x1+x2+...+xk)n.TheInputTheinputwillconsistofasetofpairsoflines.Thefirstlineofthepairconsistsoftwointege
u011217342
·
2013-11-07 09:00
A Greedy Knapsack Heuristic
- knapsack capacity W =
polynomial
in number of item
leonzhx
·
2013-10-30 15:00
Heuristic
NP-Complete
uva 10105 -
Polynomial
Coefficients(多项式系数)
题目连接:uva10105-PolynomialCoefficients题目大意:给出n和m,再该出m个数值n1~nm,保证n1+...+nm=n,现在有算式(a1+a2+...+am)^n,求展开项中a1^n1+a2^n2+...+am^nm这项的系数。解题思路:(a+b)^n的系数为C(i,n),那么对于算式(a1+a2+...+am)^n可以理解成(X+am)^n,类似于递归的操作。#inc
u011328934
·
2013-10-27 16:00
(多项式特性4.7.7)POJ 2126 Factoring a
Polynomial
(判断一个多项式能否被分解)
/* *POJ_2126.cpp * *Createdon:2013年10月26日 *Author:Administrator */ #include #include usingnamespacestd; intmain(){ intn; while(scanf("%d",&n)!=EOF){ /** *一个多项式是否能被分解的原则: *n2:能被分解 *n==2:若b^2-4*a*c>=
caihongshijie6
·
2013-10-26 18:00
(多项式运算4.7.6)POJ 2527
Polynomial
Remains(多项式除法)
例[编辑]计算把被除式、除式按某个字母作降幂排列,并把所缺的项用零补齐,写成以下这种形式:然后商和余数可以这样计算:将分子的第一项除以分母的最高次项(即次数最高的项,此处为x)。结果写在横线之上(x3 ÷ x = x2).将分母乘以刚得到结果(最终商的第一项),乘积写在分子前两项之下(同类项对齐)(x2 · (x − 3)= x3 − 3x2).从分子的相应项中减去刚得到的乘积(消去相等项,把不相
caihongshijie6
·
2013-10-26 10:00
(数组的应用三:多项式的表示与处理4.3.1)POJ 1555
Polynomial
Showdown(多项式的输出)
/* *poj_1555.cpp * *Createdon:2013年10月25日 *Author:Administrator */ #include #include #include #include usingnamespacestd; constintn=9;//指数由8~0是有9个数字的 intmain(){ inta[n]; while(scanf("%d",&a[0])!=E
caihongshijie6
·
2013-10-25 16:00
UVA - 10105
Polynomial
Coefficients
题意:求多项式的系数,套用公式:由(a+b+...+z)^n=n!/(k!*...z!)*a^k*b^d*...*f^z(k+d+...z=n);#include #include #include usingnamespacestd; constintMAXN=50; intans[MAXN],m,k,a; voidinit(){ ans[0]=1; for(inti=1;i<13;i++)
u011345136
·
2013-10-19 11:00
NP-Completeness
Polynomial
-Time Solvability -- A problem is
polynomial
-time solvable if there
leonzhx
·
2013-10-15 15:00
NP-Completeness
UVa 10719 Quotient
Polynomial
(数学)
10719-QuotientPolynomialTimelimit:3.000secondshttp://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=99&page=show_problem&problem=1660Apolynomialofdegree n canbeexpressedasIf k
synapse7
·
2013-09-15 15:00
C++
ACM
uva
hdu
Polynomial
Problem
有点杂乱无章,考虑各种情况就行了。 #include #include #include #include usingnamespacestd; #defineINF0x3fffffff #defineMAXN100001 intmain() { intn,m,x,flag,mul,ans; charstr[MAXN]; while(~scanf("%d",&x)){
ljd4305
·
2013-09-12 09:00
很多Machine Learning的问题都可以归结为regression
General的regression,我们看做,givenx1vector,x2vector,...,xnvector,来求fit这个datasample最合适的functionor分布,首先可以用
polynomial
xyqzki
·
2013-09-04 08:00
UVA10719- Quotient
Polynomial
思路:还是推公式,可以得到a[i+1]-=b[i]*(-k);#include #include #include intmain(){ intk=0,r; inta[10005],b[10005]; while(scanf("%d",&k)!=EOF){ intcnt=0; charch; memset(a,0,sizeof(a)); memset(b,0,sizeof(b)); while
u011345461
·
2013-08-16 19:00
uva 10719 Quotient
Polynomial
(多项式相除)
Apolynomialofdegree n canbeexpressedasIf k isanyintegerthenwecanwrite:Here q(x) iscalledthequotientpolynomialof p(x) ofdegree (n-1) and r isanyintegerwhichiscalledtheremainder.Forexample,if p(x)=x3 -7
u011328934
·
2013-07-31 12:00
UVA 10719 Quotient
Polynomial
QuotientPolynomialTimeLimit2SecondsApolynomialofdegree n canbeexpressedasIf k isanyintegerthenwecanwrite:Here q(x) iscalledthequotientpolynomialof p(x) ofdegree (n-1) and r isanyintegerwhichiscalledth
u011217342
·
2013-07-31 00:00
10719 - Quotient
Polynomial
ProblemBQuotientPolynomialTimeLimit2SecondsApolynomialofdegree n canbeexpressedasIf k isanyintegerthenwecanwrite:Here q(x) iscalledthequotientpolynomialof p(x) ofdegree (n-1) and r isanyintegerwhichis
SIOFive
·
2013-07-23 22:00
uva
循环链表实现多项式计算
不记得是从哪里转来的了,我修改了一下,加了多项式相减(
Polynomial
::poly_dec),计算结果(
Polynomial
::evaluate)和解析多项式字符串(
Polynomial
::parse
huanghongxun
·
2013-07-22 13:00
两个多项式的加法
include #include typedefstructPNode { doublecoef;//系数 intexp;//指数 structPNode*next;//指向下一结点的指针 }PNode,*
Polynomial
huanfengyun
·
2013-06-01 18:00
算法
加法
多项式
uva10105 -
Polynomial
Coefficients(多项式系数)
杨辉三角和二项式定理的应用。。。水题,,,,代码如下:#include intn,k; intc[15][15]; intinit() { for(inti=0;i<=13;i++) { c[i][0]=1; for(intj=1;j<=i;j++) c[i][j]=c[i-1][j]+c[i-1][j-1]; } return0; } intmain() { init(); while(~sca
shankeliupo
·
2013-05-16 19:00
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