postorder 第7页

后序遍历

structStNode{Node*node;intTimesPop;StNode(Node*N=null)：node(N),TimesPop(0){}};templatevoidBinaryTree::postOrder

山呀海莫斯·2020-06-27 01:02

Binary Tree Postorder Traversal

题目Givenabinarytree,returnthepostordertraversalofitsnodes'values.Forexample:Givenbinarytree{1,#,2,3},1\2/3return[3,2,1].Note:Recursivesolutionistrivial,couldyoudoititeratively?要求求二叉树后序遍历结果，且是非递归的算法。解题思

u010814766·2020-06-26 23:14

Interview Question - Give a preorder/postorder array of BST, reconstruct BST

问题：给你一个BST的pre-order/post-orderarray，reconstruct出这个BSTpre-orderprivateintcounter_Pre=0;publicTreeNoderestoreBST_Pre(int[]nums){returnhelper_Pre(nums,Integer.MIN_VALUE,Integer.MAX_VALUE);}privateTreeNo

Richardo92·2020-06-26 14:58

Construct Binary Tree from Inorder and Postorder Traversal 根据中序、后序遍历序列构建二叉树（Java）

题目：Giveninorderandpostordertraversalofatree,constructthebinarytree.Note:Youmayassumethatduplicatesdonotexistinthetree.解答：本题根据树的中序遍历和后序遍历，得到树的结构。与LeetCode105思路基本一致整体思路为：后序遍历的最后一个节点一定是根节点，根据后序遍历确定根节点后，在

volador_r·2020-06-25 21:27

Binary Tree and Recursion

DFSNon-recursion(usestack)Recursion（自己调用自己）--Traversal--DivideandConquerBinaryTreePreorder:根左右Inorder：左根右Postorder

IvyFan2017·2020-06-25 20:22

二叉树

上图遍历顺序是：1，2，4，5，33.后序（Postorder）：Left->Right->Root。上图遍历顺序是：4，5，2，3，1复杂度我们都知道O(n)表示时间复杂度是线性，那

last_edc·2020-06-25 20:29

LeetCode889. 根据前序和后序遍历构造二叉树

题目来源：https://leetcode-cn.com/problems/construct-binary-tree-from-preorder-and-postorder-traversal/题目描述

晨初听雨·2020-06-25 15:03

【Golang】LeetCode-剑指Offer-面试题33-二叉搜索树的后序遍历序列【两种解法】

参考以下这颗二叉搜索树：5/\26/\13示例1：输入:[1,6,3,2,5]输出:false示例2：输入:[1,3,2,6,5]输出:true提示：数组长度postorder[head]{popinter

士多啤梨先生·2020-06-25 00:41

Binary Tree Postorder Traversal-Python-LeetCode

145.BinaryTreePostorderTraversalGivenabinarytree,returnthepostordertraversalofitsnodes'values.Example:Input:[1,null,2,3]1\2/3Output:[3,2,1]Followup:Recursivesolutionistrivial,couldyoudoititeratively?F

云外雁行斜丶·2020-06-24 01:09

二叉树

binary-tree-inorder-traversalbinary-tree-pathsbinary-tree-postorder-traversalbinary-tree-preorder-traversalconstruct-binary-tree-from-inorder-and-postorder-traversalconstruct-binary-tree-from-preorder

xihe·2020-06-23 16:25

morris遍历

通常，实现二叉树的前序（preorder）、中序（inorder）、后序（postorder）遍历有两个常用的方法：一是递归(recursive)，二是使用栈实现的迭代版本(stack+iterative

RabbitMQ！！！·2020-06-23 13:09

Leetcode 889. 根据前序和后序遍历构造二叉树

：https://leetcode-cn.com/contest/weekly-contest-98/problems/construct-binary-tree-from-preorder-and-postorder-traversal

gaorongchao1990626·2020-06-23 09:15

LeetCode 145 Binary Tree Postorder Traversal

题目Givenabinarytree,returnthepostordertraversalofitsnodes'values.Example:Input:[1,null,2,3]1\2/3Output:[3,2,1]Followup:Recursivesolutionistrivial,couldyoudoititeratively?解法思路（一）借助栈；借助辅助类Command；关于辅助类Co

乌鲁木齐001号程序员·2020-06-22 19:17

Construct Binary Tree from Inorder and Postorder Traversal

Giveninorderandpostordertraversalofatree,constructthebinarytree.Note:Youmayassumethatduplicatesdonotexistinthetree.一刷思路同105/***Definitionforabinarytreenode.*publicclassTreeNode{*intval;*TreeNodeleft;*

Jeanz·2020-06-22 14:59

72.Construct Binary Tree from Inorder and Postorder Traversal-中序遍历和后序遍历树构造二叉树（中等题）

中序遍历和后序遍历树构造二叉树题目根据中序遍历和后序遍历树构造二叉树注意事项你可以假设树中不存在相同数值的节点样例给出树的中序遍历：[1,2,3]和后序遍历：[1,3,2]返回如下的树：题解由后序遍历定义可知，后序遍历序列的最后一个元素是根节点。由中序遍历定义可知，可以在中序遍历结果中遍历查找根节点，可将中序遍历序列分为左右子树，这样左右子树的长度也就确定了，在后序遍历序列中，可以确定左右子树的根

tri_color_flag·2020-06-22 07:32

LeetCode：二叉树的后序遍历（递归与非递归法）

=NULL){postOrder(root

一只爱喝酸奶的猫·2020-06-21 19:14

根据前序遍历和后序遍历构造二叉树（Construct Binary Tree from Preorder and Postorder Traversal）

889.ConstructBinaryTreefromPreorderandPostorderTraversal来源：LeetCode889.ConstructBinaryTreefromPreorderandPostorderTraversal题目描述889.ConstructBinaryTreefromPreorderandPostorderTraversalReturnanybinarytr

MrDing_CoolPig·2020-06-20 22:52

A 1138 Postorder Traversal (25分)（二叉树知道先序、中序遍历推后序遍历）

一、技术总结已知包含中序遍历，在随便知道先序或是后序，遍历都是能够确定二叉树，create函数模板要记住。不要忘记root->data=in[k]赋值。递归边界，返回的是returnNULL。同时，就是后序遍历了，return没有的。二、参考代码#include#includeusingnamespacestd;structnode{intv;node*L,*R;};vectorin,pre,po

睿晞·2020-06-17 21:00

Leetcode 106. 从中序与后序遍历序列构造二叉树(分治算法)

Example中序遍历inorder=[9,3,15,20,7]后序遍历postorder=[9,15,7,20,3]题目链接：106.从中序与后序遍历序列构造二叉树(难度:中等)思路树的后序遍历顺序为

进击的Lancelot·2020-06-15 17:15

常考算法面试题系列：树的遍历

根据根节点，左孩子节点和右孩子节点的访问顺序又可以将DFS细分为先序遍历preorder，中序遍历inorder和后序遍历postorder。广

木子星兮·2020-06-04 01:15

MXC肖某某·2020-04-22 22:00

10.二叉树简介及先序、中序、后序

大纲：二叉树介绍先序/中序/后序Preorder/inorder/postorder分治算法Divide&Conquer二叉树的宽度优先遍历二叉树搜索树翻转二叉树Homebrew作者MarkHowell

偷天神猫·2020-04-13 03:41

binary-tree-postorder-traversal[后序遍历]

题目描述Givenabinarytree,returnthepostordertraversalofitsnodes'values.Forexample:Givenbinarytree{1,#,2,3},return[3,2,1].Note:Recursivesolutionistrivial,couldyoudoititeratively?思路求后序遍历。法一：递归（参考中序遍历）法二：非递归。

是我真的是我·2020-04-12 21:02

Construct Binary Tree from Inorder and Postorder Traversal

ConstructBinaryTreefromInorderandPostorderTraversal.png解題思路：利用post-order的尾端找到root的值再用root值去inorder找到root在inorder中的index接著用inorder的頭到index-1的範圍當作左子數的範圍index+1到index尾的範圍當右邊子樹的範圍繼續recursive注意在recursive裡面

一枚煎餅·2020-04-11 02:39

Binary Tree Postorder Traversal

题目Givenabinarytree,returnthepostordertraversalofitsnodes'values.Forexample:Givenbinarytree{1,#,2,3},1\2/3return[3,2,1].Note:Recursivesolutionistrivial,couldyoudoititeratively?答案classSolution{publicLis

BLUE_fdf9·2020-04-10 23:49

Binary Tree Postorder Traversal

同样的遍历过程，可以考虑用一个Stack保存先序遍历的结果，随后将stack内的值逐个POP。这里要求先左再右，如果在原有的遍历过程中仍然是以左半部分为优先的话，在pop后会变成右先左后，所以要从右边开始。/***Definitionforabinarytreenode.*publicclassTreeNode{*intval;*TreeNodeleft;*TreeNoderight;*TreeN

misleadingrei·2020-04-05 02:14

Construct Binary Tree from Inorder and Postorder Traversal

题目Giveninorderandpostordertraversalofatree,constructthebinarytree.Note:Youmayassumethatduplicatesdonotexistinthetree.解题之法/***Definitionforbinarytree*structTreeNode{*intval;*TreeNode*left;*TreeNode*rig

时光杂货店·2020-04-04 07:54

Binary Tree Inorder/Preorder/Postorder Traversal (M/M/H)

Description(Inorder,94):Givenabinarytree,returntheinordertraversalofitsnodes'values.Example:Input:[1,null,2,3]12/3Output:[1,3,2]Followup:Recursivesolutionistrivial,couldyoudoititeratively?Solutions:Tr

Ysgc·2020-04-03 22:02

Construct Binary Tree from Inorder and Postorder Traversal (Medium)

constructthebinarytree.Note:Youmayassumethatduplicatesdonotexistinthetree.Forexample,giveninorder=[9,3,15,20,7]postorder

Ysgc·2020-04-02 20:45

106. 从中序与后序遍历序列构造二叉树(leetcode)

例如，给出中序遍历inorder=[9,3,15,20,7]后序遍历postorder=[9,15,7,20,3]返回如下的二叉树：3/\920/\157代码/***Definitionforabinarytreenode

6默默Welsh·2020-03-28 18:13

【2错】Binary Tree Tilt

https://leetcode.com/problems/binary-tree-tilt/日期是否一次通过comment2018-12-2614:01看答案，并手推复现对postOrder理解不够深

7ccc099f4608·2020-03-26 01:27

Construct Binary Tree from Inorder and Postorder Traversal

Youmayassumethatduplicatesdonotexistinthetree.Solution1:Recursive做法Example:12345678910Inorder:849251*10637Postorder

sherwin29·2020-03-25 23:24

Construct Binary Tree from Inorder and Postorder Traversal(中序遍历和后序遍历树构造二叉树)

问题Giveninorderandpostordertraversalofatree,constructthebinarytree.**NoticeYoumayassumethatduplicatesdonotexistinthetree.Haveyoumetthisquestioninarealinterview?YesExampleGiveninorder[1,2,3]andpostorder

天街孤独·2020-03-21 22:58

N-ary Tree Postorder Traversal

文章作者：Tyan博客：noahsnail.com|CSDN|1.DescriptionN-aryTreePostorderTraversal2.SolutionRecursive/*//DefinitionforaNode.classNode{public:intval;vectorchildren;Node(){}Node(int_val,vector_children){val=_val;c

SnailTyan·2020-03-21 05:48

军迷日更12:互联时代的“后真相”

2017年度幕尼黑安全会议的主报告中提出了当前国际形势的三大特点：后真相（posttruth),后西方(postwest),后秩序(postorder)。今天草根哥说说后真相。

草根说国际·2020-03-17 02:10

Binary Tree Postorder Traversal

Givenabinarytree,returnthepostordertraversalofitsnodes'values.Forexample:Givenbinarytree{1,#,2,3},return[3,2,1].Note:Recursivesolutionistrivial,couldyoudoititeratively?题意：后序遍历，即左右中。思路：1、分治递归遍历左右中。publ

ShutLove·2020-03-16 17:21

Binary Tree Postorder Traversal 二叉树后序遍历

题目链接tag:Hard；question： Givenabinarytree,returnthepostordertraversalofitsnodes'values.Example:Input:[1,null,2,3]1\2/3Output:[3,2,1]Followup:Recursivesolutionistrivial,couldyoudoititeratively?思路：那么在9

xingzai·2020-03-16 15:49

Binary Tree Postorder Traversal

Givenabinarytree,returnthepostordertraversalofitsnodes'values.Forexample:Givenbinarytree{1,#,2,3},1\2/3return[3,2,1].Note:Recursivesolutionistrivial,couldyoudoititeratively?classSolution{public:vector

juexin·2020-03-15 19:50

Construct Binary Tree from Inorder and Postorder Traversal

Giveninorderandpostordertraversalofatree,constructthebinarytree.Note:Youmayassumethatduplicatesdonotexistinthetree.classSolution{public:TreeNode*createTree(vector&inorder,intin_start,intin_end,vector&

juexin·2020-03-14 18:34

Binary Tree Postorder Traversal

145.BinaryTreePostorderTraversal题目:https://leetcode.com/problems/binary-tree-postorder-traversal/难度:Hardwikipedia

oo上海·2020-03-08 01:44

297. Serialize and Deserialize Binary Tree

https://leetcode.com/problems/serialize-and-deserialize-binary-tree/description/本以为需要将Tree变成preorder/postorder

Super_Alan·2020-03-05 14:33

Leetcode - Binary Tree Postorder Traversal

Paste_Image.pngMycode:importjava.util.ArrayList;importjava.util.List;/***Definitionforabinarytreenode.*publicclassTreeNode{*intval;*TreeNodeleft;*TreeNoderight;*TreeNode(intx){val=x;}*}*/publicclassSo

Richardo92·2020-03-02 19:55

Leetcode 145.binary tree postorder traversal

原题地址：https://leetcode.com/problems/binary-tree-postorder-traversal/description/题目描述Givenabinarytree,returnthepostordertraversalofitsnodes'values

岛上痴汉·2020-02-28 15:41

145 binary tree postorder traversal

利用两个stack,根节点先入栈S1,弹出的通知把两个孩子按照左右的顺序加入S1，并把自己加入S2，依次循环直到S1为空，然后依次S2出栈保存[1,2,3]s1:23s2:1s1:2s2:13s1:0s2:132S2出栈就是231完成了后序访问structStack{structListNode*dummy;};voidpush(structStack*s,intval){structListNo

larrymusk·2020-02-26 14:00

Construct Binary Tree from Inorder and Postorder Traversal

分类：Tree时间复杂度:O(n)这种把树的节点都遍历一遍的情况时间复杂度为O(n)空间复杂度:O(h)树的节点的深度106.ConstructBinaryTreefromInorderandPostorderTraversalGiveninorderandpostordertraversalofatree,constructthebinarytree.Note:Youmayassumethatd

野生小熊猫·2020-02-26 00:45

leetcode之二叉树

目录1.binary-tree-preorder-traversal2.binary-tree-postorder-traversal3.binary-tree-inorder-traversal4.binary-tree-level-order-traversal5

Nibaby燕·2020-02-25 21:11

Binary Tree Postorder Traversal

思路相当于preordertraversal的逆过程。关键逆过程1：巧用LinkedList的addFirst方法，先pop的节点实际上为输出中靠后的节点。逆过程2：新pop的节点既然在输出中更靠后，因此让right节点先pop，即先是left节点入栈，后是right节点入栈。...while(!stack.empty()){cur=stack.pop();rst.addFirst(cur.val

kevinscake·2020-02-25 17:09

Binary Tree Postorder Traversal

BinaryTreePostorderTraversal.png解題思路：postorder的recursive解法left,right,self如果要使用iterative的做法可以用stack來做放進

一枚煎餅·2020-02-24 00:53

Leetcode-145题:Binary Tree Postorder Traversal

题目非递归后序遍历代码#Definitionforabinarytreenode.#classTreeNode(object):#def__init__(self,x):#self.val=x#self.left=None#self.right=NoneclassSolution(object):defpostorderTraversal(self,root):""":typeroot:TreeN

八刀一闪·2020-02-18 14:41

LeetCode 106 [Construct Binary Tree from Inorder and Postorder Traversal]

原题中序遍历和后序遍历树构造二叉树给出树的中序遍历：[1,2,3]和后序遍历：[1,3,2]返回如下的树：2/\13你可以假设树中不存在相同数值的节点解题思路首先明确，前序+后序遍历的组合不能还原一棵二叉树后序遍历的最后一个点是根节点，参照此根节点可以将中序遍历数组分成左右两部分，分别为左子树和右子树依据以上思路递归重建二叉树完整代码#Definitionforabinarytreenode.#c

Jason_Yuan·2020-02-18 07:10

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