uva1636 Headshot

You have a revolver gun with a cylinder that has n chambers. Chambers
are located in a circle on a cylinder. Each chamber can be empty or
can contain a round. One chamber is aligned with the gun’s barrel.
When trigger of the gun is pulled, the gun’s cylinder rotates,
aligning the next chamber with the barrel, hammer strikes the round,
making a shot by ring a bullet through the barrel. If the chamber is
empty when the hammer strikes it, then there is no shot but just a
\click”. You have found a use for this gun. You are playing Russian
Roulette with your friend. Your friend loads rounds into some
chambers, randomly rotates the cylinder, aligning a random chamber
with a gun’s barrel, puts the gun to his head and pulls the trigger.
You hear \click” and nothing else | the chamber was empty and the gun
did not shoot. Now it is your turn to put the gun to your head and
pull the trigger. You have a choice. You can either pull the trigger
right away or you can randomly rotate the gun’s cylinder and then pull
the trigger. What should you choose to maximize the chances of your
survival? Input The input le contains several datasets. A dataset
consists of a single line with a string of n digits 0 ' and 1 ’ (2
 n  100). This line of digits represents the pattern of rounds that
were loaded into the gun’s chambers. 0 ' represent an empty chamber,
1 ’ represent a loaded one. In this representation, when cylinder
rotates before a shot, the next chamber to the right gets aligned with
the barrel for a shot. Since the chambers are actually located on a
circle, the rst chamber in this string follows the last one. There is
at least one 0 ' in this string. Output For each dataset, write to
the output le one of the following words (without quotes):  SHOOT
’ | if pulling the trigger right away makes you less likely to be
actually shot in the head with the bullet (more likely that the
chamber will be empty).  ROTATE ' | if randomly rotating the
cylinder before pulling the trigger makes you less likely to be
actually shot in the head with the bullet (more likely that the
chamber will be empty).  EQUAL ’ | if both of the above choices are
equal in terms of probability of being shot.

直接射击没有子弹的概率是（00的个数）/（0的个数）。
转一下再射击没有子弹的概率是（0的个数）/（总数）。

#include
#include
char s[110];
int main()
{
    int i,j,k,m,n,p,q,x,y,z,cnt_0,cnt_00;
    while (scanf("%s",s+1)==1)
    {
        n=strlen(s+1);
        cnt_0=cnt_00=0;
        for (i=1;i<=n;i++)
          if (s[i]=='0')
          {
            cnt_0++;
            if ((is[i+1]=='0')||(i==n&&s[1]=='0'))
              cnt_00++;
          }
        if (cnt_00*n>cnt_0*cnt_0) printf("SHOOT\n");
        else
        {
            if (cnt_00*n0*cnt_0) printf("ROTATE\n");
            else printf("EQUAL\n");
        }
    }
}