CodeForces 46DParking Lot线段树

 

 对于100的查询,用线段树搞。。

还是队友帮我调的,= =!错的很2b。同hotel搞法,只不过把他变长了,好处理头和为的停车位置。

#include <cstdio>

#include <cstring>

#include <algorithm>

#include <climits>

#include <string>

#include <iostream>

#include <map>

#include <cstdlib>

#include <list>

#include <set>

#include <queue>

#include <stack>

#include<math.h>

#include<vector>

using namespace std;



const int maxn = 111111;

int sum[maxn << 2]; int lsum[maxn << 2], rsum[maxn << 2], color[maxn << 2];

int q[maxn], q1[maxn];

#define lson l,mid,rt<<1

#define rson mid+1,r,rt<<1|1



void up(int rt, int m)

{

    lsum[rt] = lsum[rt << 1];

    rsum[rt] = rsum[rt << 1 | 1];

    if (lsum[rt] == (m - (m >> 1))) lsum[rt] += lsum[rt << 1 | 1];

    if (rsum[rt] == (m >> 1)) rsum[rt] += rsum[rt << 1];

    sum[rt] = max(max(sum[rt << 1], sum[rt << 1 | 1]), rsum[rt << 1] + lsum[rt << 1 | 1]);

}



void down(int rt, int m)

{

    if (~color[rt]){

        color[rt << 1] = color[rt << 1 | 1] = color[rt];

        sum[rt << 1] = lsum[rt << 1] = rsum[rt << 1] = color[rt] ? 0 : (m - (m >> 1));

        sum[rt << 1 | 1] = lsum[rt << 1 | 1] = rsum[rt << 1 | 1] = color[rt] ? 0 : (m >> 1);

        color[rt] = -1;

    }

}



void build(int l, int r, int rt)

{

    color[rt] = -1; sum[rt] = lsum[rt] = rsum[rt] = r - l + 1;

    if (l == r) return;

    int mid = (l + r) >> 1;

    build(lson);

    build(rson);

}



void update(int L, int R, int add, int l, int r, int rt)

{

    if (L <= l&&r <= R){color[rt] = add;

        sum[rt] = lsum[rt] = rsum[rt] = color[rt] ? 0 : r - l + 1;

         return;

    }

    down(rt, r - l + 1);

    int mid = (l + r) >> 1;

    if (L <= mid) update(L, R, add, lson);

    if (R > mid) update(L, R, add, rson);

    up(rt, r - l + 1);

}



int ask(int key, int l, int r, int rt)

{

    if (l == r) return l;

    int mid = (l + r) >> 1;

    down(rt, r - l + 1);

    if (sum[rt << 1] >= key) return ask(key, lson);

    if (rsum[rt << 1] + lsum[rt << 1 | 1] >= key) return mid - rsum[rt << 1] + 1;

    return ask(key, rson);

}



int main()

{

    int n, a, b, c, d, m;

    scanf("%d%d%d", &n, &c, &d);

    build(1, c + n + d, 1);

    scanf("%d", &m);

    for (int i = 1; i <= m; i++){

        scanf("%d%d", &a, &b);

        if (a == 1){

            if (c + b + d > sum[1]){

                printf("-1\n"); continue;

            }

            int t = ask(c + b + d, 1, c + n + d, 1);

            printf("%d\n",t - 1);

            update(c + t, c + t + b - 1, 1, 1, c + n + d, 1);

            q[i] = t; q1[i] = b;

        }

        else{

            update(c + q[b], c + q[b] + q1[b] - 1, 0, 1, c + n + d, 1);

        }

    }

    return 0;



}

 

你可能感兴趣的:(codeforces)