给n个红点,m个蓝点,问是否找到一条直线,使得直线一侧全是红点,另一侧全是蓝点。
对两种点分别求凸包,然后就是判断两个凸包是否相离了..如果相离就是Yes否则就是No.判断相离就是枚举没一条边,看是否和另一个凸包相交就行了。另外还要考虑包含的情况,这里就需要判断一下是否存在某个点存在于另一类点的凸包内部。
#include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <string> #include <cmath> #include <vector> typedef double type; using namespace std; const double PI=acos(-1.0); const double eps=1e-13; struct Point { type x,y; Point(){} Point(type a,type b) { x=a; y=b; } void read() { scanf("%lf%lf",&x,&y); } void print() { printf("%.6lf %.6lf",x,y); } }; typedef Point Vector; Vector operator + (Vector A,Vector B) { return Vector(A.x+B.x,A.y+B.y); } Vector operator - (Point A,Point B) { return Vector(A.x-B.x,A.y-B.y); } Vector operator * (Vector A,type p) { return Vector(A.x*p,A.y*p); } Vector operator / (Vector A,type p) { return Vector(A.x/p,A.y/p); } bool operator < (const Point &a,const Point &b) { return a.x<b.x || (a.x==b.x && a.y<b.y); } int dcmp(double x) { if (fabs(x)<eps) return 0; else return x<0?-1:1; } bool operator == (const Point& a,const Point b) { return dcmp(a.x-b.x)==0 && dcmp(a.y-b.y)==0; } //atan2(x,y) :向量(x,y)的极角,即从x轴正半轴旋转到该向量方向所需要的角度。 type Dot(Vector A,Vector B) { return A.x*B.x+A.y*B.y; } type Cross(Vector A,Vector B) { return A.x*B.y-A.y*B.x; } type Length(Vector A) { return sqrt(Dot(A,A)); } type Angle(Vector A,Vector B) { return acos(Dot(A,B))/Length(A)/Length(B); } type Area2(Point A,Point B,Point C) { return Cross(B-A,C-A); } Vector Rotate(Vector A,double rad) { return Vector(A.x*cos(rad)-A.y*sin(rad),A.x*sin(rad)+A.y*cos(rad)); } Vector Normal(Vector A)//单位法线,左转90度,长度归一 { double L=Length(A); return Vector(-A.y/L,A.x/L); } Point GetLineIntersection(Point P,Vector v,Point Q,Vector w) { Vector u=P-Q; double t=Cross(w,u)/Cross(v,w); return P+v*t; } double DistanceToLine(Point P,Point A,Point B) { Vector v1=B-A,v2=P-A; return fabs(Cross(v1,v2))/Length(v1); } double DistanceToSegment(Point P,Point A,Point B) { if (A==B) return Length(P-A); Vector v1=B-A,v2=P-A,v3=P-B; if (dcmp(Dot(v1,v2))<0) return Length(v2); else if (dcmp(Dot(v1,v3))>0) return Length(v3); else return fabs(Cross(v1,v2))/Length(v1); } Point GetLineProjection(Point P,Point A,Point B)//P在AB上的投影 { Vector v=B-A; return A+v*(Dot(v,P-A)/Dot(v,v)); } bool SegmentProperIntersection(Point a1,Point a2,Point b1,Point b2) { double c1=Cross(a2-a1,b1-a1),c2=Cross(a2-a1,b2-a1), c3=Cross(b2-b1,a1-b1),c4=Cross(b2-b1,a2-b1); return dcmp(c1)*dcmp(c2)<0 && dcmp(c3)*dcmp(c4)<0; } bool OnSegment(Point p,Point a1,Point a2) { return dcmp(Cross(a1-p,a2-p))==0 && dcmp(Dot(a1-p,a2-p))<0; } double ConvexPolygonArea(Point* p,int n)//多边形面积 { double area=0; for (int i=1; i<n-1; i++) area+=Cross(p[i]-p[0],p[i+1]-p[0]); return area/2.0; } double PolygonArea(Point* p,int n)//有向面积 { double area=0; for (int i=1; i<n-1; i++) area+=Cross(p[i]-p[0],p[i+1]-p[0]); return area/2.0; } struct Line { Point p; Vector v; double ang; Line(){}; Line(Point PP,Vector vv) { p=PP; v=vv; ang=atan2(v.y,v.x); } bool operator< (const Line& L)const { return ang<L.ang; } Point point(double t) { return p+v*t; } }; struct Circle { Point c; double r; Circle() { } Circle(Point cc,double rr) { c=cc; r=rr; } Point point(double a) { return Point(c.x+cos(a)*r,c.y+sin(a)*r); } }; int getLineCircleIntersection(Line L,Circle C,double& t1,double &t2,vector<Point>& sol) { double a=L.v.x, b=L.p.x-C.c.x, c=L.v.y, d=L.p.y-C.c.y; double e=a*a+c*c,f=2*(a*b+c*d), g=b*b+d*d-C.r*C.r; double delta=f*f-4*e*g;//判别式 if (dcmp(delta)<0) return 0;//相离 if (dcmp(delta)==0) { t1=t2=-f/(2*e); sol.push_back(L.point(t1)); return 1; }//相切 t1=(-f-sqrt(delta))/(2*e); sol.push_back(L.point(t1)); t2=(-f+sqrt(delta))/(2*e); sol.push_back(L.point(t2)); return 2; } double angle(Vector v)//向量极角 { return atan2(v.y,v.x); } int getCircleCircleIntersection(Circle C1,Circle C2,vector<Point>& sol) { double d = Length(C1.c-C2.c); if (dcmp(d)==0) { if (dcmp(C1.r-C2.r)==0) return -1; return 0; } if (dcmp(C1.r+C2.r-d)<0) return 0; if (dcmp(fabs(C1.r-C2.r)-d)>0) return 0; double a=angle(C2.c-C1.c); double da= acos((C1.r*C1.r+d*d-C2.r*C2.r)/(2*C1.r*d)); Point p1=C1.point(a-da),p2=C1.point(a+da); sol.push_back(p1); if (p1==p2) return 1; sol.push_back(p2); return 2; } int getTangents(Point p,Circle C,Vector* v) { Vector u=C.c-p; double dist=Length(u); if (dist<C.r) return 0; else if (dcmp(dist-C.r)==0) { v[0]=Rotate(u,PI/2); return 1; } else { double ang=asin(C.r/dist); v[0]=Rotate(u,-ang); v[1]=Rotate(u,+ang); return 2; } } int getTangents(Circle A,Circle B,Point* a,Point* b) { int cnt=0; if (A.r<B.r) { swap(A,B); swap(a,b); } int d2=(A.c.x-B.c.x)*(A.c.x-B.c.x)+(A.c.y-B.c.y)*(A.c.y-B.c.y); int rdiff=A.r-B.r; int rsum=A.r+B.r; if (d2<rdiff*rdiff) return 0; double base=atan2(B.c.y-A.c.y,B.c.x-A.c.x); if (d2==0 && A.r==B.r) return -1; if (d2==rdiff*rdiff) { a[cnt]=A.point(base); b[cnt]=B.point(base); cnt++; return 1; } double ang=acos((A.r-B.r)/sqrt(d2)); a[cnt]=A.point(base+ang); b[cnt]=B.point(base+ang); cnt++; a[cnt]=A.point(base-ang); b[cnt]=B.point(base-ang); cnt++; if (d2==rsum*rsum) { a[cnt]=A.point(base); b[cnt]=B.point(PI+base); cnt++; } else if (d2>rsum*rsum) { double ang=acos((A.r+B.r)/sqrt(d2)); a[cnt]=A.point(base+ang); b[cnt]=B.point(PI+base+ang); cnt++; a[cnt]=A.point(base-ang); b[cnt]=B.point(PI+base-ang); cnt++; } return cnt; } int isPointInpolygon(Point p,Point* poly,int n) { int wn=0; for (int i=0; i<n; i++) { if (OnSegment(p,poly[i],poly[(i+1)%n]) || p==poly[i] || p==poly[(i+1)%n]) return -1; int k=dcmp(Cross(poly[(i+1)%n]-poly[i],p-poly[(i+1)%n])); int d1=dcmp(poly[i].y-p.y); int d2=dcmp(poly[(i+1)%n].y-p.y); if (k>0 && d1<=0 && d2>0) wn++; if (k<0 && d2<=0 && d1>0) wn--; } if (wn!=0) return 1; else return 0; } int ConvexHull(Point *p, int n,Point *ch) { sort(p,p+n); int m=0; for (int i=0; i<n; i++) { while(m>1 && Cross(ch[m-1]-ch[m-2],p[i]-ch[m-2])<=0) m--; ch[m++]=p[i]; } int k=m; for (int i=n-2; i>=0; i--) { while(m>k && Cross(ch[m-1]-ch[m-2],p[i]-ch[m-2])<=0) m--; ch[m++]=p[i]; } if (n>1) m--; return m; } Point b[660],r[660],chb[660],chr[660]; int n,m; int main() { // freopen("in.txt","r",stdin); while(~scanf("%d%d",&n,&m)) { if (!n && !m) break; for (int i=0; i<n; i++) r[i].read(); for (int i=0; i<m; i++) b[i].read(); int sr=ConvexHull(r,n,chr); int sb=ConvexHull(b,m,chb); bool ok=true; for (int i=0; i<sr; i++) { int i1=(i+1)%sr; for (int j=0; j<sb; j++) { int j1=(j+1)%sb; if (SegmentProperIntersection(chr[i],chr[i1],chb[j],chb[j1])) { ok=false; i=sr; j=sb; break; } } } if (ok) { for (int i=0; i<sr; i++) { int t=(isPointInpolygon(chr[i],chb,sb)); if (t==-1 || t==1) { ok=false; break; } } } if (ok) { for (int i=0; i<sb; i++) { int t=isPointInpolygon(chb[i],chr,sr); if (t==-1 || t==1) { ok=false; break; } } } if (ok) puts("Yes"); else puts("No"); } }