HDU1792(数论)

A New Change Problem

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 668    Accepted Submission(s): 337

Problem Description

Now given two kinds of coins A and B,which satisfy that GCD(A,B)=1.Here you can assume that there are enough coins for both kinds.Please calculate the maximal value that you cannot pay and the total number that you cannot pay.

 

Input

The input will consist of a series of pairs of integers A and B, separated by a space, one pair of integers per line.

 

Output

For each pair of input integers A and B you should output the the maximal value that you cannot pay and the total number that you cannot pay, and with one line of output for each line in input.

 

Sample Input

   
   
   
   

    
    
    
    2 3
3 4
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    1 1
5 3
   
   
   
   
   
   
   
   

    
    
    
     
   
   
   
   
   
   
   
   

    
    
    
    数论题，不知道的同学可以找规律
   
   
   
   
   
   
   
   

    
    
    
    最大不能表示:n*m-n-m
   
   
   
   
   
   
   
   

    
    
    
    所有不能表示的个数:(m-1)*(n-1)/2
   
   
   
   
   
   
   
   

    
    
    
     
   
   
   
   
   
   
   
   

    
    
    
    
#include<iostream>
#include<cstdio>
using namespace std;

__int64 n,m;
int main()
{
	while(~scanf("%I64d%I64d",&n,&m))
	{
		printf("%I64d %I64d\n",n*m-n-m,(n-1)*(m-1)/2);
	}
	return 0;
}