poj2250 Compromise--最长公共子序列+打印序列+单词非字符

原题链接:http://poj.org/problem?id=2250


#include
#include
#include
#include
using namespace std;

string s1[105];
string s2[105];
int dp[105][105];
int len1, len2;

void dfs(int i, int j)
{
    if (i == 0 || j == 0)
        return;
    if (s1[i] == s2[j])
    {
        dfs(i - 1, j - 1);
        cout << s1[i] << " ";
    }
    else
    {
        if (dp[i - 1][j] > dp[i][j - 1])
            dfs(i - 1, j);
        else
            dfs(i, j - 1);
    }

}

int main()
{
    string s;

    while (cin >> s)
    {
        len1 = 0;
        if (s != "#")
        {
            s1[++len1] = s;
            while (cin >> s&&s != "#")
                s1[++len1] = s;
        }
        len2 = 0;
        while (cin >> s&&s != "#")
            s2[++len2] = s;

        for (int i = 1; i <= len1; i++)
        {
            for (int j = 1; j <= len2; j++)
            {
                if (s1[i] == s2[j])
                    dp[i][j] = dp[i - 1][j - 1] + 1;
                else
                    dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);
            }
        }

        dfs(len1, len2);
        cout << endl;
    }

    return 0;
}

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