HDOJ-----1398---Square Coins---简单DP

Square Coins

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12013    Accepted Submission(s): 8230


Problem Description
People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (=17^2), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.
There are four combinations of coins to pay ten credits:

ten 1-credit coins,
one 4-credit coin and six 1-credit coins,
two 4-credit coins and two 1-credit coins, and
one 9-credit coin and one 1-credit coin.

Your mission is to count the number of ways to pay a given amount using coins of Silverland.
 

Input
The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.
 

Output
For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.
 

Sample Input
 
   
2 10 30 0
 

Sample Output
 
   
1 4 27

外星人有17种硬币的面值,分别是1*1 2*2 …… 17*17,问给一个金额,有几种面值的方法组成

dp[j]表示金额为j的可以由几种面值组成,预处理一下就好,简单dp

#include
#include
#include
#include
#include
#include
#include
#include
#include
#define PI acos(-1.0)
#define inf 0x3f3f3f3f
using namespace std; 
const int maxn = 1e5+10;
typedef long long LL;
using namespace std;
int dp[400], val[20];
int main(){
	int n, x, y;
	for(int i = 1; i < 18; i++) val[i] = i*i;
	dp[0] = 1;
	for(int i = 1; i < 18; i++){
		for(int j = val[i]; j < 301; j++) dp[j] += dp[j-val[i]];
	}
	while(cin >> n && n) cout << dp[n] << endl;
	return 0;
}

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