"If you have an apple and I have an apple and we exchange these apples then you and I will still each have one apple. But if you have an idea and I have an idea and we exchange these ideas, then each of us will have two ideas." - George Bernard Shaw
Now Alice has A apples and B ideas, while Bob has C apples and D ideas, what will they have if they exchange all things?
There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:
The only line contains four integers A, B, C, D (0 <= A, B, C, D <= 100) - as the problem described.
For each test case, output two lines. First line contains two integers, indicating the number of Alice's apples and ideas; second line contains two integers, indicating the number of Bob's apples and ideas.
4 0 0 5 30 20 25 20 0 20 25 20 15 20 25 25 30
5 30 0 30 20 25 20 25 20 40 20 40 25 55 20 55Author: DAI, Longao
Source: The 13th Zhejiang Provincial Collegiate Programming Contest
省赛第一道,大水题,两分钟一A
#include<cstdio> #include<algorithm> using namespace std; typedef long long LL; const int maxn = 1e5 + 4; int T, a, b, c, d; int main() { scanf("%d", &T); while (T--) { scanf("%d%d%d%d", &a, &b, &c, &d); printf("%d %d\n%d %d\n", c, b + d, a, b + d); } return 0; }