HDU 6129 lucas判断组合数奇偶性

Just do it

Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)
Total Submission(s): 1106    Accepted Submission(s): 641


Problem Description
There is a nonnegative integer sequence  a1...n of length  n. HazelFan wants to do a type of transformation called prefix-XOR, which means  a1...n changes into  b1...n, where  bi equals to the XOR value of  a1,...,ai. He will repeat it for  m times, please tell him the final sequence.
 

Input
The first line contains a positive integer  T(1T5), denoting the number of test cases.
For each test case:
The first line contains two positive integers  n,m(1n2×105,1m109).
The second line contains  n nonnegative integers  a1...n(0ai2301).
 

Output
For each test case:
A single line contains  n nonnegative integers, denoting the final sequence.
 

Sample Input
 
   
2 1 1 1 3 3 1 2 3
 

Sample Output
 
   
1 1 3 1


能A的代码都是从da[i]对答案的贡献的角度去考虑的  实际上的复杂度也是o(n2)   其实正着去推的复杂度也是o(n2)  不知道为什么后者就过不去  而且时间会长很多很多。

不过这也给了我教训  考虑问题要从多个角度去考虑.

注意判断组合数的奇偶性    (a&b)==b那么  C(a,b)就是奇数   另外  注意 &运算优先级低于==运算    


#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#define maxlen 200100

using namespace std;
int m;int n;
int da[maxlen];
int ans[maxlen];
int main()
{
	/*
	freopen("test.txt","w",stdout);
    cout<<200000<<" "<<21434234<


你可能感兴趣的:(多校)