SRM627 div2 1000pt DP

Problem Statement
	The pseudocode shown below is an implementation of BubbleSort. Note that the array A used in the implementation is 0-based. That is, elements of A have indices 0 through Length(A)-1, inclusive. BubbleSort(A): Repeat Length(A)-1 times: For every i from 0 to Length(A)-2, inclusive: If A[i] > A[i+1] then: Swap A[i] and A[i+1] We are going to sort the array A using the above algorithm. However, before we do that, you are allowed to reverse at most K disjoint subarrays of A. For example, suppose that A={10, 20, 30, 40, 50, 60, 70} and that K=1. In this case you may, for example, reverse the subarray [2,5] - that is, the elements at (0-based) indices 2 through 5. This would produce the array {10, 20, 60, 50, 40, 30, 70}. We are interested in minimizing the number of swaps executed by our BubbleSort. You are given the vector  A and the int K. Return the smallest possible number of swaps performed by our BubbleSort after you reverse at most K disjoint subarrays of A.
Definition
	Class: BubbleSortWithReversals Method: getMinSwaps Parameters: vector , int Returns: int Method signature: int getMinSwaps(vector A, int K) (be sure your method is public)
Limits
	Time limit (s): 2.000 Memory limit (MB): 256
Constraints
-	A will contain between 2 and 50 elements.
-	K will be between 1 and 50.
-	Each element of A will be between 1 and 1000, inclusive.
Examples
0)
	{6,8,8,7,7} 1 Returns: 0 By reversing the subarray [1,4] we obtain a new array {6,7,7,8,8}. This array is already sorted and we can easily verify that our BubbleSort never swaps anything.
1)
	{7,2,2,13,5,5,2} 2 Returns: 3
2)
	{12,5,1,10,12,6,6,10,6,8} 2 Returns: 12
3)
	{2,3,1} 2 Returns: 1 Note that the subarrays we are reversing must all be disjoint. For example, it is not allowed to reverse first the subarray [0,1] and then the subarray [0,2].
4)
	{482,619,619,601,660,660,691,691,77,77,96,77} 9 Returns: 22

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题目大意：给一个A数组和一个数字K，求最多做K次不相交连续子区间的翻转，使得最终得倒的数组冒泡排序的交换次数最少

题目模型：逆序数+DP

对于一次区间交换，改变的只是该区间的逆序数

用dp[i][j]表示前i个数做了j次交换的最小答案，考虑之前的区间[k+1,j],是否做交换，再从dp[i][k]转移过来即可。

#include 
#include 
#include 
#include 
#define inf 0x3f3f3f3f
using namespace std;
class BubbleSortWithReversals{
	public:
    int dp[55][55];
    vector B;
    int calc(int x,int y){
        int d=0,c=0;
        for(int i=x;i<=y;i++){
            for(int j=i+1;j<=y;j++){
                if(B[j]>B[i]) d++;
            }
            for(int j=0;jB[i]) c++;
            }
        }
        return d+c;
    }
    int calc2(int x,int y){
        int d=0;
        for(int i=x;i<=y;i++){
            for(int j=0;jB[i]) d++;
            }
        }
        return d;
    }
	int getMinSwaps(vector  A, int K){
	    this->B=A;
		int n=A.size();
        memset(dp,0x3f,sizeof dp);
        dp[0][0]=0;
        for(int i=1;i<=n;i++){
            for(int j=0;j