POJ2778

刷AC自动机，很久以前做过，再系统地做一便，发现之前dp矩阵的裸体都过不了。玄学修改后就行了（板子问题？？？）

记录一下

#include
#include
#include
using namespace std;
#define ll long long
int ch[105][5];
int root = 0;
ll mod = (ll)1e5;
int fail[105], val[105], sz;

char rea[4] = {'A', 'T', 'C', 'G'};

int react(char c)
{
    if (c == 'A')
        return 0;
    if (c == 'T')
        return 1;
    if (c == 'C')
        return 2;
    if (c == 'G')
        return 3;
}

void init()
{
    sz = 0;
    root = 0;
    val[0] = 0;
    for (int i = 0; i <= 3; i++)
        ch[root][i] = root;
}

int newnode()
{
    sz++;
    val[sz] = 0;
    for (int i = 0; i < 4; i++)
        ch[sz][i] = 0;
    return sz;
}

void build(char buf[])
{
    int cur = root;
    int len = strlen(buf);
    for (int i = 0; i < len; i++)
    {
        int c = react(buf[i]);
        if (ch[cur][c] == root)
        {
            int u = newnode();
            ch[cur][c] = u;
        }
        cur = ch[cur][c];
    }
    val[cur] = 1;
}

void getfail()
{
    int cur = root;
    queue q;
    for (int i = 0; i <= 3; i++)
    {
        if (ch[root][i] == root)
        {
            continue;
        }
        int u = ch[root][i];
        fail[u] = root;
        q.push(u);
    }
    while (!q.empty())
    {
        int u = q.front();
        q.pop();
        val[u] |= val[fail[u]];
        for (int i = 0; i <= 3; i++)
        {
            int v = ch[u][i];
            if (v == root)
            {
                ch[u][i] = ch[fail[u]][i];
                continue;
            }
            fail[v] = ch[fail[u]][i];
            q.push(v);
        }
    }
}

struct matrix
{
    ll a[105][105];

    matrix()
    {
        for (int i = 0; i <= sz; i++)
            for (int j = 0; j <= sz; j++)
                a[i][j] = 0;
    }

    ll* operator [] (int i)
    {
        return a[i];
    }
};

matrix base;

matrix mult(matrix a, matrix b)
{
	matrix ans;
	for (int i = 0; i <= sz; i++)
	{
		for (int j = 0; j <= sz; j++)
		{
			for (int k = 0; k <= sz; k++)
			{
				ans[i][j] += a[i][k] * b[k][j] % mod;
				ans[i][j] %= mod;
			}
		}
	}
	return ans;
}

void get_base()
{
    for (int cur = root; cur <= sz; cur++)
    {
        if (val[cur])
            continue;
        for (int i = 0; i <= 3; i++)
        {
            if (val[ch[cur][i]])
                continue;
            base[cur][ch[cur][i]]++;
        }
    }
}

template
void read(T& ret)
{
    ret = 0;
    char c;
    while ((c = getchar()) > '9' || c < '0');
    while (c >= '0' && c <= '9')
    {
        ret = ret * 10 + c - '0';
        c = getchar();
    }
}
char s[100];

int main()
{
    int m;
    ll n;
    read(m), read(n);
    init();
    for (int i = 1; i <= m; i++)
    {
        scanf("%s", s);
        build(s);
    }
    getfail();
    matrix ans;
    for (int i = 0; i <= sz; i++)
        ans[i][i] = 1;
    get_base();

    while (n)
    {
        if (n & 1)
            ans = mult(ans, base);
        base = mult(base, base);
        n >>= 1;
    }
    
    ll sum = 0;
    for (int i = 0; i <= sz; i++)
        sum = (sum + ans[0][i]) % mod;
    printf("%lld\n", sum);

    return 0;
}