2602

HDU 2602 Bone Collector

1.题目描述：点击打开链接2.解题思路：本题就是经典的01背包问题，i逆序枚举的写法就不介绍了，主要说一下经典的错误写法。如果将输入的n个物品下标设为0~n-1，给出正确的写法和错误的写法。3.代码：（正确的写法）//#pragmacomment(linker,"/STACK:1024000000,1024000000") #include #include #include #include #
u014800748·2015-08-19 23:00

HDU2602

Q-BoneCollectorDescriptionManyyearsago,inTeddy’shometowntherewasamanwhowascalled“BoneCollector”.Thismanliketocollectvariesofbones,suchasdog’s,cow’s,alsohewenttothegrave…Thebonecollectorhadabigbagwitha
mrlry·2015-08-19 11:00

HDOJ 2602 Bone Collector（01背包）

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):39999    AcceptedSubmission(s):16595ProblemDescriptionManyyearsago,inTeddy’shometowntherewasa
helloiamclh·2015-08-18 15:00

HDU 2602 Bone Collector

HDU2602BoneCollectorProblemDescriptionManyyearsago,inTeddy’shometowntherewasamanwhowascalled“BoneCollector
qq_21120027·2015-08-16 16:00

hdu oj 2602 Bone Collector

hduoj2602BoneCollector题目：BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(
baidu_30541191·2015-08-15 15:00

hdu2602-Bone Collector （背包）

 BoneCollectorDescriptionManyyearsago,inTeddy’shometowntherewasamanwhowascalled“BoneCollector”.Thismanliketocollectvariesofbones,suchasdog’s,cow’s,alsohewenttothegrave…Thebonecollectorhadabigbagwithav
lljjccsskk·2015-08-13 21:00

hdu2602 Bone Collector(背包问题)

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):39612    AcceptedSubmission(s):16412ProblemDescriptionManyyearsago,inTeddy’shometowntherewasa
su20145104009·2015-08-12 09:00

hdu 2602 Bone Collector 01背包

经典的01背包问题，去年集训的时候没有做出来的题目，原来是如此简单。。。思路：dp[i+1][j]代表选前i个骨头总容量不超过j的最大价值，所以可得到状态方程|dp[i+1][j]=dp[i][j](vol[i]>j当前i的容量大于j) ||dp[i+1][j]=max{dp[i][j],dp[i][j-vol[i]]+val[i]}|(当前i的容量小于j，只存在装与不装第i个骨头，所以选择最大的
sinat_22659021·2015-08-08 15:00

HDU 2602 Bone Collector（01背包）

题目地址：点击打开链接思路：01背包，具体看代码，还有本博客算法精讲类里TianyiCui大神写的背包9讲错误代码：#include #include intvalue[1010],volumn[1010],dp[1010][1010]; intmax(inta,intb) { returna>b?a:b; } intmain() { intt,n,v,i,j; scanf("%d",&t)
qq_25605637·2015-08-03 09:00

Training：背包专题

HDU2602：http://acm.hust.edu.cn/vjudge/problem/visitOriginUrl.action?id=1743401背包。
wcr1996·2015-06-21 10:00

HDU 2602 Bone Collector

分析：简单的01背包问题，状态转移方程为：dp[i][v]=max{dp[i-1][v],dp[i-1][v-w[i]]+val[i]},其中dp[i][v]表示前i件物品放在容量为v中的最大值。转化为一维数组的状态转移方程为：dp[v]=max{dp[v],dp[v-w[i]]+val[i]},其中循环为v=V...w[i]，保证推dp[v]时dp[v-w[i]]保存的是状态dp[i-1][v-
ZengAMing·2015-05-27 20:00

HDU 2602 解题报告

代码链接：HDU2602
cbs612537·2015-05-18 07:00

poj 大数 - 2602 Superlong sums

这应该算是最简单的大数题了。。。目的就是为了让你知道char的输入输出比int快很多，还学会了getchar()，putchar()。#include #defineMAX1000002 charnum[MAX],num1[MAX]; intmain(){ intn,i; scanf("%d",&n); getchar(); for(i=1;i=1;i--){ num[i]+=num1[i]-'
u010006643·2015-05-09 10:00

hdu 2602 Bone Collector

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):30095    AcceptedSubmission(s):12389ProblemDescriptionManyyearsago,inTeddy’shometowntherewasa
u013806814·2015-04-02 11:00

hdu 3065 病毒侵袭持续中 AC自动机

Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):7489    AcceptedSubmission(s):2602ProblemDescription
u013532224·2015-03-09 19:00

hdoj 2602 01背包入门题

pid=2602第一道01背包用了二维的方法解，二维的就是要注意在遍历背包容量时要从零开始，并且判断是否大于该物品的消耗，如果大于的话在考虑是否放入，否则直接就是不能放。
liujc_·2015-03-01 15:00

HDU 2602 Bone Collector

FontSize: ← →ProblemDescriptionManyyearsago,inTeddy’shometowntherewasamanwhowascalled“BoneCollector”.Thismanliketocollectvariesofbones,suchasdog’s,cow’s,alsohewenttothegrave…Thebonecollectorhadabigbag
jtjy568805874·2015-02-18 16:00

hdu 2602 Bone Collector

#include #include #include #include #include usingnamespacestd; intmain() { intt,n,v,i,j,w[1024],s[1024],d[1024]; scanf("%d",&t); while(t--) { memset(d,0,sizeof(d)); scanf("%d%d",&n,&v); for(i=0;i=s[
xinag578·2015-02-17 11:00

HDOJ 2602 Bone Collector【01背包】

pid=2602BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission
u012560612·2015-02-15 11:00

2602 0/1背包

#include #include #include #include #defineMAX10007 usingnamespacestd; intdp[MAX]; intw[MAX]; intc[MAX]; intmain() { unsignedt,n,m; scanf("%d",&t); while(t--) { scanf("%d%d",&n,&m); for(inti=1;i=c[
qq_24451605·2015-02-01 00:00

mactex自动更新tex live utilities错误

/runme.sh:CannotfindTeXLiverootusingkpsewhich--var-value=SELFAUTOPARENT. 2014-12-2602:39:16+0000Warningtlu_ipctask
QIBAOYUAN·2014-12-30 10:00

hdu2602 Bone Collector （01背包裸题）

pid=2602#include #include #include #include usingnamespacestd; structhdu2602{ intval; intv; }a[10
f1024042400·2014-12-25 19:00

HDU 2602 Bone Collector

pid=2602                             BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768
·2014-12-15 20:00

背包问题

pid=2602BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission
Enjoying_Science·2014-11-25 10:00

HDU2602 Bone Collector 01背包问题 动态规划

01背包问题是典型的动态规划问题，他是这样描述的：有n件物品和一个质量为m的背包（每种物品只有一件），第i件物品的质量为w（i），价值是p（i），求解将哪些物品装入背包可以使价值总和最大。这是最基本的背包问题，特点是对于每一件物品，只有两种状态：即装入背包，或者不装。我们用f（i，v）来表示前i件物品放入一个容量为v的背包里可以获得的最大价值，那么很容易可以得出它的状态转移方程：f（i，v）=ma
AC_Gibson·2014-11-24 11:00

HDU-2602-Bone Collector （最基础DP！！）

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):31922    AcceptedSubmission(s):13138ProblemDescriptionManyyearsago,inTeddy’shometowntherewasa
u014355480·2014-11-22 15:00

Hduoj2602【01背包】

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):31842    AcceptedSubmission(s):13104ProblemDescriptionManyyearsago,inTeddy’shometowntherewasa
u014641529·2014-11-20 22:00

HDU - 2602 Bone Collector （01背包）

解析：01背包的模板题dp公式为：dp[i][j]=max(dp[i][j],dp[i-1][j-v[i]]+w[i]);#include #include #include usingnamespacestd; constintN=1010; intn,V; intw[N],v[N]; intdp[N][N]; intmain(){ intt; scanf("%d",&t); while(t-
HelloWorld10086·2014-11-15 20:00

hdu- 2602 Bone Collector

ProblemDescriptionManyyearsago,inTeddy’shometowntherewasamanwhowascalled“BoneCollector”.Thismanliketocollectvariesofbones,suchasdog’s,cow’s,alsohewenttothegrave…Thebonecollectorhadabigbagwithavolumeof
wojiaohuangyu·2014-11-09 22:00

HDU2602_Bone Collector【01背包】

BoneCollectorTimeLimit:2000/1000MS(Java/Others)  MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):31133  AcceptedSubmission(s):12805ProblemDescriptionManyyearsago,inTeddy’shometowntherewasamanw
u011676797·2014-10-20 16:00

[原]hdu2602 Bone Collector (01背包）

//============================================================================ //Name:2602.cpp //Author
svtter·2014-10-17 23:00

hdu2602 Bone Collector (01背包）

//============================================================================ //Name:2602.cpp //Author
svtter·2014-10-17 23:00

hdu2602 Bone Collector (01背包）

//============================================================================ //Name:2602.cpp //Author
svtter·2014-10-17 23:00

hdu 2602 Bone Collector （01背包）

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):30553    AcceptedSubmission(s):12576ProblemDescriptionManyyearsago,inTeddy’shometowntherewasa
xky1306102chenhong·2014-09-14 20:00

iOS:Objective-C 关键字1

=============self、super========================--参考：http://www.cocoachina.com/macdev/objc/2011/0124/2602
houseq·2014-08-12 11:00

hduoj2602Bone Collector

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):29163    AcceptedSubmission(s):11922ProblemDescriptionManyyearsago,inTeddy’shometowntherewa
u012678352·2014-08-01 10:00

HDU2602 Bone Collector 【01背包】

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):28365    AcceptedSubmission(s):11562ProblemDescriptionManyyearsago,inTeddy’shometowntherewasa
u012846486·2014-07-19 23:00

背包问题—杭电2602 Bone Collector

pid=2602BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission
u013263923·2014-04-19 12:00

2014.4.19 背包问题

一、01背包问题dp[i][j]=max(dp[i-1][v[i]],dp[i-1][w[i]-c[i]]+w[i])例：2602http://acm.hdu.edu.cn/showproblem.php
u013263923·2014-04-19 11:00

HDU 2602 Bone Collector(DP:01背包)

HDU2602BoneCollector(DP:01背包)http://acm.hdu.edu.cn/showproblem.php?
u013480600·2014-04-02 18:00

HDU 2602 Bone Collector(01背包)

题目链接：HDU2602BoneCollector01背包。最基础的01背包。
fobdddf·2014-03-23 11:00

[ACM] hdu 2602 Bone Collector(01背包)

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):25042    AcceptedSubmission(s):10147ProblemDescription Manyyearsago,inTeddy’shometowntherewas
sr19930829·2014-03-20 17:00

HDU 2602 Bone Collector (简单的0-1背包）

BoneCollectorTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):24860    AcceptedSubmission(s):10062ProblemDescriptionManyyearsago,inTeddy’shometowntherewasa
IAccepted·2014-03-15 11:00

hdu 2602 Bone Collector

01背包的状态转换方程 f[i,j]=Max{f[i-1,j-Wi]+Pi(j>=Wi), f[i-1,j]}f[i,j]表示在前i件物品中选择若干件放在承重为j的背包中，可以取得的最大价值。Pi表示第i件物品的价值。决策：为了背包中物品总价值最大化，第i件物品应该放入背包中吗？#include #include intdp[1010][1010],w[1010],val[1010]; in
u013365671·2014-03-08 19:00

HDU-2602 Bone Collector

http://acm.hdu.edu.cn/showproblem.php?pid=260201背包：用二维数组实现。c[n][m]表示n种物品，背包容量为m的最大价值。状态方程为:f(n,m)=max{f(n-1,m),f(n-1,m-w[n])+P(n,m)}这就是书本上写的动态规划方程.             BoneCollectorTimeLimit:2000/1000MS(Java/
·2014-02-25 21:00

hdu 2602 Bone Collector(01背包)

TimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):24175    AcceptedSubmission(s):9809ProblemDescriptionManyyearsago,inTeddy’shometowntherewasamanwhowascalle
u013081425·2014-02-20 10:00

HDU 2602 Bone Collector (经典0-1背包)

pid=2602/*31ms,240KB*/ #include #include #include usingnamespacestd; constintmx=1005; intw[mx],v[mx
synapse7·2014-02-20 05:00

hdu 2602 背包问题之01背包

pid=2602ProblemDescriptionManyyearsago,inTeddy’shometowntherewasamanwhowascalled“BoneCollector”.Thismanliketocollectvariesofbones
u013573047·2014-02-15 12:00

01背包 HDU2602

#include intnn[10000],p[10000],f[10000][10000]; intmax(inta,intb) { returna>b?a:b; } intmain() { intm,i,j,n,v; scanf("%d",&m); while(m--) { scanf("%d%d",&n,&v); for(i=1;i=p[i]) f[i][j]=max(f[i-1][j],f
u013476556·2014-02-12 13:00

最健脾养胃的8种食物

最健脾养胃的8种食物来源:39健康网|2013-12-2602:20:00A-A+评论 分享中医专家表示，女性平胸，乳房下垂很多见，这和中国女性普遍脾气虚有直接关系，所以，能丰胸的食物首先肯定是能健脾的食物
sleks·2014-01-01 22:00
上一页 4 5 6 7 8 9 10 11 下一页
按字母分类： ABCDEFGHIJKLMNOPQRSTUVWXYZ其他